The reaction between lead(II) nitrate (Pb(NO3)2) and potassium iodide (KI) is a double displacement reaction. The lead cation (Pb2+) swaps its nitrate anions (NO3-) with the potassium cation (K+) in the reactants, forming lead(II) iodide (PbI2) and potassium nitrate (KNO3).
The balanced reaction is: 2Cl + 2KI → 2KCl + I2. It is balanced by ensuring there are the same number of each type of atom on both sides of the reaction arrow.
This is a double displacement reaction, also known as a metathesis reaction. In this reaction, the chlorine atoms in Cl2 and the iodide ions in KI swap partners to form potassium chloride (KCl) and iodine (I2).
To balance the reaction Cl2 + KI -> KCl + I2, you just need to place a coefficient of 2 in front of KCl to balance the number of chlorine atoms on both sides of the reaction. The balanced reaction is Cl2 + 2KI -> 2KCl + I2.
The balanced equation for the reaction would be: 2ClO + 2HCl + C6H10O5 + 2KI → 2KCl + 2H2O + CO2 + I2.
The reaction between potassium iodide (KI) and dilute sulfuric acid (H2SO4) can be represented by the following equation: 2KI + H2SO4 -> 2KHSO4 + HI
The balanced reaction is: 2Cl + 2KI → 2KCl + I2. It is balanced by ensuring there are the same number of each type of atom on both sides of the reaction arrow.
This is a double displacement reaction, also known as a metathesis reaction. In this reaction, the chlorine atoms in Cl2 and the iodide ions in KI swap partners to form potassium chloride (KCl) and iodine (I2).
To balance the reaction Cl2 + KI -> KCl + I2, you just need to place a coefficient of 2 in front of KCl to balance the number of chlorine atoms on both sides of the reaction. The balanced reaction is Cl2 + 2KI -> 2KCl + I2.
2KI + Cl2 = 2KCl + I2
The balanced equation for the reaction would be: 2ClO + 2HCl + C6H10O5 + 2KI → 2KCl + 2H2O + CO2 + I2.
2ki + h2o2 = 2koh +i2
2KI + F2 ----> 2KF + I2I hope this help :) :P :D :} :]
The reaction between potassium iodide (KI) and dilute sulfuric acid (H2SO4) can be represented by the following equation: 2KI + H2SO4 -> 2KHSO4 + HI
This is a double displacement reaction where bromine (Br2) reacts with potassium iodide (KI) to form potassium bromide (KBr) and iodine (I2) by exchanging ions. The bromine displaces the iodine from potassium iodide to form potassium bromide and free iodine.
you have to write... 2KI + Cl2 = 2KCl + I2
2KI + HgCl₂ -----> 2KCl + HgI₂
Chlorine gas reacts with potassium iodide to produce potassium chloride and iodine. This reaction can be represented by the chemical equation: Cl2 + 2KI -> 2KCl + I2.