Redox reaction.
Cl2 + 2KI --> 2KCl + I2
This is a combination or synthesis reaction. 2 atoms of K (potassium) combine with a diatomic molecule I2 (iodine) to form two molecules of KI (potassium iodide).
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3 is a precipitation reaction. The PbI2 is insoluble in water and will precipitate. It is NOT neutralization, because you do not have an acid reacting with a base.
Assuming a double displacement reaction. 2KI + BaS --> K2S + BaI2
2ki+ h2so4 ----> k2so4 + 2hi
2KI + HgCl₂ -----> 2KCl + HgI₂
2KI + Cl2 = 2KCl + I2
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
I is replaced by Cl.So KCl and I2 is formed.
Cl2 + 2KI --> 2KCl + I2
Cl2(g) + 2KI(aq) arrow 2KCl(aq) + I2(s)
you have to write... 2KI + Cl2 = 2KCl + I2
2KI + Cl2 = 2KCl + I2
This is the correct answer: Cl2(g)+2KI(aq) = I2(s)+2KCl(aq)
2ki and 2kci
This is a combination or synthesis reaction. 2 atoms of K (potassium) combine with a diatomic molecule I2 (iodine) to form two molecules of KI (potassium iodide).
2ki + h2o2 = 2koh +i2