Cl2(g) + 2KI(aq) arrow 2KCl(aq) + I2(s)
When chlorine gas is added to potassium iodide solution, potassium chloride and iodine are formed. The balanced chemical equation for this reaction is 2KI + Cl2 → 2KCl + I2.
you have to write... 2KI + Cl2 = 2KCl + I2
As a stronger oxidizing agent than Iodine, Chlorine oxidizes the Iodide ions to Elementary Iodine, while itself gets reduced to Chloride. The equation for this reaction is:Cl2 + 2 I- ----> 2 Cl- + I2
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
2KI + Cl2 = 2KCl + I2
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
The reaction between potassium iodide (KI) and chlorine gas (Cl2) forms potassium chloride (KCl) and iodine (I2). The balanced equation is 2KI + Cl2 → 2KCl + I2.
When chlorine gas is added to potassium iodide solution, potassium chloride and iodine are formed. The balanced chemical equation for this reaction is 2KI + Cl2 → 2KCl + I2.
you have to write... 2KI + Cl2 = 2KCl + I2
As a stronger oxidizing agent than Iodine, Chlorine oxidizes the Iodide ions to Elementary Iodine, while itself gets reduced to Chloride. The equation for this reaction is:Cl2 + 2 I- ----> 2 Cl- + I2
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
2KI + Cl2 = 2KCl + I2
2i + 3cl2 --> 2icl3
Chlorine gas reacts with potassium iodide to produce potassium chloride and iodine. This reaction can be represented by the chemical equation: Cl2 + 2KI -> 2KCl + I2.
The balanced chemical equation for the reaction between barium acetate and potassium iodide is: Ba(CH3COO)2 + 2KI -> BaI2 + 2KCH3COO
Br2 + (2e)- --> 2 Br- 2I- --> I2 + (2e)-
potassium