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Chlorine gas reacts with potassium iodide to produce potassium chloride and iodine. This reaction can be represented by the chemical equation: Cl2 + 2KI -> 2KCl + I2.
2KI + Cl2 = 2KCl + I2
The reaction between potassium iodide and bromine produces potassium bromide and iodine. This is a redox reaction where bromine gets reduced to bromide ions, while iodide ions get oxidized to form elemental iodine. The balanced chemical equation for this reaction is 2 KI + Br2 → 2 KBr + I2.
When potassium iodide is mixed with lead nitrate, a double displacement reaction occurs. The products formed are lead iodide and potassium nitrate. Lead iodide is a yellow precipitate that forms during the reaction.
The reaction between ethyl iodide and alcoholic potash (potassium hydroxide dissolved in alcohol) results in the formation of ethyl alcohol, potassium iodide, and potassium ethoxide. The chemical equation for this reaction can be written as: C2H5I + KOH → C2H5OH + KI + KOC2H5
Silver nitrate plus potassium iodide yields silver iodide plus potassium nitrate.
2 KBr + BaI2 ----> 2 KI + BaBr2
Chlorine gas reacts with potassium iodide to produce potassium chloride and iodine. This reaction can be represented by the chemical equation: Cl2 + 2KI -> 2KCl + I2.
The reaction represented is a single displacement reaction, where potassium (K) displaces iodine (I2) from potassium iodide (KI) to form potassium iodide and elemental iodine.
This is a double displacement reaction where bromine (Br2) reacts with potassium iodide (KI) to form potassium bromide (KBr) and iodine (I2) by exchanging ions. The bromine displaces the iodine from potassium iodide to form potassium bromide and free iodine.
The chemical equation for the reaction between ethyl iodide and aqueous potassium hydroxide is: C2H5I + KOH → C2H5OH + KI This reaction involves the substitution of the iodine in ethyl iodide with hydroxide from KOH, resulting in the formation of ethanol and potassium iodide.
2KI + Cl2 = 2KCl + I2
The reaction is the following:AgNO3 + KI = KNO3 = AgI(s)
When sodium nitrate (NaNO3) reacts with potassium iodide (KI), it forms sodium iodide (NaI) and potassium nitrate (KNO3). This reaction is a double replacement reaction, where the positive ions from each compound switch places. The chemical equation for this reaction is: NaNO3 + KI → NaI + KNO3.
When silver nitrate and potassium iodide are combined, they undergo a double displacement reaction. Silver iodide is formed as a yellow precipitate, while potassium nitrate remains in solution. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3.
When hydrogen peroxide is added to potassium iodide, it rapidly decomposes into water and oxygen gas, producing a visible foaming reaction. This reaction is a decomposition reaction that is catalyzed by the presence of iodide ions.
The reaction between potassium iodide and bromine produces potassium bromide and iodine. This is a redox reaction where bromine gets reduced to bromide ions, while iodide ions get oxidized to form elemental iodine. The balanced chemical equation for this reaction is 2 KI + Br2 → 2 KBr + I2.