2 H2O2(aq) O2(aq) + 2 H2O(aq)
2 KBr + BaI2 ----> 2 KI + BaBr2
Potassium plus Water gives Potassium Hydroxide plus Hydrogen
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
This is a double displacement reaction where bromine (Br2) reacts with potassium iodide (KI) to form potassium bromide (KBr) and iodine (I2) by exchanging ions. The bromine displaces the iodine from potassium iodide to form potassium bromide and free iodine.
The chemical equation for the reaction between ethyl iodide and aqueous potassium hydroxide is: C2H5I + KOH → C2H5OH + KI This reaction involves the substitution of the iodine in ethyl iodide with hydroxide from KOH, resulting in the formation of ethanol and potassium iodide.
H2O2 The cation hydrogen has a charge of +1, and the anion peroxide has a charge of -2, so to balance peroxide's charge we would need two hydrogen atoms, as the net (total) charge of a compound must always be zero. I am, however, unsure if peroxide is indeed an anion, but the rest of the information is correct. Look it up if in doubt.
Silver nitrate plus potassium iodide yields silver iodide plus potassium nitrate.
When iron reacts with potassium iodide, it forms potassium iodide. The reaction can be written as 2Fe + 2KI → 2K + 2FeI. Potassium iodide is a salt and is commonly used as a nutritional supplement.
2 KBr + BaI2 ----> 2 KI + BaBr2
Potassium plus Water gives Potassium Hydroxide plus Hydrogen
Chlorine gas reacts with potassium iodide to produce potassium chloride and iodine. This reaction can be represented by the chemical equation: Cl2 + 2KI -> 2KCl + I2.
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
The reaction represented is a single displacement reaction, where potassium (K) displaces iodine (I2) from potassium iodide (KI) to form potassium iodide and elemental iodine.
This is a double displacement reaction where bromine (Br2) reacts with potassium iodide (KI) to form potassium bromide (KBr) and iodine (I2) by exchanging ions. The bromine displaces the iodine from potassium iodide to form potassium bromide and free iodine.
hydrogen peroxide
The chemical equation for the reaction between ethyl iodide and aqueous potassium hydroxide is: C2H5I + KOH → C2H5OH + KI This reaction involves the substitution of the iodine in ethyl iodide with hydroxide from KOH, resulting in the formation of ethanol and potassium iodide.
When Hydrogen Peroxide (2H2O2) is combined with a small piece of liver, the hydrogen peroxide decomposes. This is because the small piece of liver acts as a catalyst, or the cause, of the decomposition of the Hydrogen Peroxide.The balanced equation is thus:2H2O2 (Hydrogen Peroxide) ---------> 2H2O + O2