Equation is
Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
Lead reacts with hydrogen nitrate to form lead(II) nitrate and hydrogen gas. The balanced chemical equation for this reaction is: Pb + 4HNO3 → Pb(NO3)2 + 2H2
The balanced equation for the decomposition of lead(II) nitrate is: 2Pb(NO3)2(s) → 2PbO(s) + 4NO2(g) + O2(g).
The balanced equation for the heating of lead(II) nitrate (Pb(NO3)2) is: 2Pb(NO3)2(s) → 2PbO(s) + 4NO2(g) + O2(g)
For lead (II) nitrate: H2SO4 + Pb(NO3)2 -----> 2HNO3 + PbSO4 ...................................................(white)
The balanced equation for the reaction between sodium chloride and lead nitrate to produce lead chloride is: 2NaCl + Pb(NO3)2 -> 2NaNO3 + PbCl2
Lead reacts with hydrogen nitrate to form lead(II) nitrate and hydrogen gas. The balanced chemical equation for this reaction is: Pb + 4HNO3 → Pb(NO3)2 + 2H2
The balanced equation for the decomposition of lead(II) nitrate is: 2Pb(NO3)2(s) → 2PbO(s) + 4NO2(g) + O2(g).
The balanced equation for the heating of lead(II) nitrate (Pb(NO3)2) is: 2Pb(NO3)2(s) → 2PbO(s) + 4NO2(g) + O2(g)
For lead (II) nitrate: H2SO4 + Pb(NO3)2 -----> 2HNO3 + PbSO4 ...................................................(white)
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
The balanced equation for the reaction between sodium chloride and lead nitrate to produce lead chloride is: 2NaCl + Pb(NO3)2 -> 2NaNO3 + PbCl2
Pb + 2NO3 - --> Pb(NO3)2
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
The balanced chemical equation for the reaction of lead foil with silver nitrate solution is: 2AgNO3 + Pb --> Pb(NO3)2 + 2Ag This reaction forms lead(II) nitrate and silver.
The balanced chemical equation for the reaction between barium bromide (BaBr2) and lead(II) nitrate (Pb(NO3)2) is: BaBr2 + Pb(NO3)2 -> 2PbBr2 + Ba(NO3)2
Perhaps a double replacement reaction? AB + CD --> AD + CB 2NaBr + Pb(NO3)2 --> PbBr2 + 2NaNO3
The balanced equation for the reaction between lead(II) nitrate (Pb(NO3)2) and sodium iodide (NaI) to form lead(II) iodide (PbI2) and sodium nitrate (NaNO3) is: Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3