The net ionic equation for the reaction between Pb(NO3)2 and KI is:
Pb2+ (aq) + 2I- (aq) -> PbI2 (s)
This represents the formation of solid lead(II) iodide.
the complete chemical equation for KI AgNO3 and HNO3.the reaction between KI and Ag NO3 can take place you asked a wrong question.AgNO3 + KI = AgI + KNO3Reaction type: double replacement
Yes, potassium iodide (KI) is an ionic compound. It is composed of potassium cations (K+) and iodide anions (I-), which are held together by ionic bonds due to the transfer of electrons from potassium to iodine.
KI is an ionic compound composed of a metal (potassium) and a non-metal (iodine). It forms an ionic bond where potassium donates an electron to iodine, resulting in the formation of K+ cation and I- anion.
The one that is ionic is KI, potassium iodide.
lead nitrate(Pb(NO3)2 + potassium iodide(KI) = lead iodide(PbI) + potassium nitrate (KNO3)
The net ionic equation for the reaction between aqueous potassium iodide (KI) and aqueous lead(II) nitrate (Pb(NO3)2) is: 2I- (aq) + Pb2+ (aq) → PbI2 (s)
There is no real "net ionic" equation, as KI is a catalyst that decomposes H2O2. The "slow step" is H2O2 + I- --> OI- + H2O The "fast step" is H2O2 + OI- --> H2O + I- O2 The overall is: 2 H2O2 --> 2H2O + O2
the complete chemical equation for KI AgNO3 and HNO3.the reaction between KI and Ag NO3 can take place you asked a wrong question.AgNO3 + KI = AgI + KNO3Reaction type: double replacement
When lead(II) nitrate (Pb(NO₃)₂) is mixed with potassium iodide (KI) in solution, a double displacement reaction occurs, resulting in the formation of lead(II) iodide (PbI₂), which is a precipitate, and potassium nitrate (KNO₃) in solution. The complete ionic equation for this reaction can be written as: [ \text{Pb}^{2+} (aq) + 2 \text{NO}_3^{-} (aq) + 2 \text{K}^{+} (aq) + 2 \text{I}^{-} (aq) \rightarrow \text{PbI}_2 (s) + 2 \text{K}^{+} (aq) + 2 \text{NO}_3^{-} (aq) ] This equation illustrates the dissociation of the soluble ions in solution and the formation of the insoluble lead(II) iodide precipitate.
The chemical equation is: (K+ + I-)(aq) + (Ag+ + [NO3]-)(aq) --> AgI (s) + (K+ + [NO3]-)(aq) or The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
No- KI, Potassium iodide is an ionic compound.
Yes, potassium iodide (KI) is an ionic compound. It is composed of potassium cations (K+) and iodide anions (I-), which are held together by ionic bonds due to the transfer of electrons from potassium to iodine.
KI is an ionic compound composed of a metal (potassium) and a non-metal (iodine). It forms an ionic bond where potassium donates an electron to iodine, resulting in the formation of K+ cation and I- anion.
The one that is ionic is KI, potassium iodide.
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
The balanced equation for KI + BaS is 2Kl + BaS -> BaI2 + K2S.
The formula for potassium iodide is KI.