Potassium iodide and lead nitrate produces golden yellow precipitate of lead iodide and potassium nitrate. This reaction is a double displacement reaction and also it can be called a precipitation reaction as lead iodide gets precipitated.
2KI+Pb(NO3)2-->PbI2 + 2KNO3
This equation is:
Pb(NO3)2 + 2 KI = 2 KNO3 + PbI2
Lead iodide is an yellow precipitate.
The chemical equation is:
Pb(NO3)2 + 2 KI = PbI2(s) + 2 KNO3
The chemical equation is:
KI + Pb(NO3)2 = PbI2(s) + 2 KNO3
its a double replacement reaction
Pb(NO3)2 + 2KI -----> PbI2 +2KNO3
I dont know
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
A yellow precipitate of silver iodiode (AgI) is formed.
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Ag(NO3)(aq) + KI(aq) ---> K(NO3)(aq) + AgI(s)
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
No, reaction
lead nitrate(Pb(NO3)2 + potassium iodide(KI) = lead iodide(PbI) + potassium nitrate (KNO3)
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
A yellow precipitate of silver iodiode (AgI) is formed.
The products are Mercury(II) iodide and Potassium nitrate
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Potassium nitrate and a precipitate of Silver iodide are formed
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Both
It produces Potassium nitrate and Lead iodide
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.