Ag(NO3)(aq) + KI(aq) ---> K(NO3)(aq) + AgI(s)
A yellow precipitate of lead iodide is formed due to the reaction between potassium iodide and lead nitrate. This reaction is a double displacement reaction, where the potassium from potassium iodide swaps places with the lead from lead nitrate, forming the insoluble lead iodide.
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
When potassium iodide is added to lead nitrate, a precipitation reaction occurs resulting in the formation of lead iodide, a yellow insoluble solid, and potassium nitrate, which remains in solution. This reaction can be visually identified by the formation of a yellow precipitate.
Silver nitrate solution and potassium iodide solution can be mixed to form silver iodide due to a double displacement reaction where the silver ions from silver nitrate react with the iodide ions from potassium iodide to form insoluble silver iodide precipitate. The balanced chemical equation for this reaction is: AgNO3 (aq) + KI (aq) → AgI (s) + KNO3 (aq).
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
A yellow precipitate of lead iodide is formed due to the reaction between potassium iodide and lead nitrate. This reaction is a double displacement reaction, where the potassium from potassium iodide swaps places with the lead from lead nitrate, forming the insoluble lead iodide.
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
potassium nitrate would be left was an aqueous solution and lead iodide would be the precipitate
The compound precipitate formed when potassium iodide is added to a solution of lead nitrate is lead iodide, which is a yellow precipitate. This reaction is a double displacement reaction where the potassium ion and nitrate ion switch partners to form potassium nitrate and lead iodide.
When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
Silver iodide (AgI), a precipitate insoluble in water, don't react with potassium nitrate.
When potassium iodide is added to lead nitrate, a precipitation reaction occurs resulting in the formation of lead iodide, a yellow insoluble solid, and potassium nitrate, which remains in solution. This reaction can be visually identified by the formation of a yellow precipitate.
You can separate lead iodide precipitate and potassium nitrate solution by filtration. Pour the mixture through a filter paper in a funnel to trap the solid lead iodide, allowing the clear potassium nitrate solution to pass through. The lead iodide will be left on the filter paper, which can then be washed with water to remove any remaining potassium nitrate before drying the solid lead iodide.
When potassium iodide and lead nitrate are combined, a double displacement reaction occurs, resulting in the formation of lead iodide and potassium nitrate. Lead iodide is a yellow precipitate that forms when the two solutions are mixed.
The products are Mercury(II) iodide and Potassium nitrate
When a solution of potassium iodide is added to lead nitrate, a yellow precipitate of lead iodide is formed. This is a double displacement reaction where the cations and anions switch partners to form the products.