Silver iodide (AgI), a precipitate insoluble in water, don't react with potassium nitrate.
When potassium iodide and lead nitrate are combined, a double displacement reaction occurs, resulting in the formation of lead iodide and potassium nitrate. Lead iodide is a yellow precipitate that forms when the two solutions are mixed.
When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.
The products are Mercury(II) iodide and Potassium nitrate
When potassium iodide reacts with barium nitrate, a double displacement reaction occurs. The potassium ions and barium ions switch places to form potassium nitrate and barium iodide. Both products are insoluble and will form a precipitate.
A yellow precipitate of lead iodide is formed due to the reaction between potassium iodide and lead nitrate. This reaction is a double displacement reaction, where the potassium from potassium iodide swaps places with the lead from lead nitrate, forming the insoluble lead iodide.
A white precipitate of silver iodide forms due to the reaction between silver ions and iodide ions, leaving potassium nitrate in solution. This reaction is a double displacement reaction and is used as a test for iodide ions.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
The reaction between silver nitrate and potassium iodide forms silver iodide precipitate and potassium nitrate. This reaction is a double displacement reaction where the silver ions from silver nitrate switch places with the potassium ions in potassium iodide.
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
potassium nitrate would be left was an aqueous solution and lead iodide would be the precipitate
When silver nitrate and potassium iodide are combined, they undergo a double displacement reaction. Silver iodide is formed as a yellow precipitate, while potassium nitrate remains in solution. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3.
When solutions of lead nitrate and potassium iodide are mixed, a yellow precipitate of lead iodide is formed. This reaction is a double displacement reaction where the lead from lead nitrate reacts with the iodide from potassium iodide to form the insoluble lead iodide.