Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s)
PbI2 is a yellow coloured solid and will precipitate out of the solution.
pb(No3)2 +2KI -------> 2KNo3+pbI2
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
Potassium nitrate and a precipitate of Silver iodide are formed
It produces Potassium nitrate and Lead iodide
A reaction doesn't occur.
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
The products are Mercury(II) iodide and Potassium nitrate
Potassium nitrate and a precipitate of Silver iodide are formed
It produces Potassium nitrate and Lead iodide
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
A reaction doesn't occur.
A precipitate of Lead iodide and Potassium nitrate are formed
potassium
Ag(NO3)(aq) + KI(aq) ---> K(NO3)(aq) + AgI(s)