A precipitation reaction occurs. Yellow precipitates of lead iodide are formed. The equation for this reaction is
Pb(NO3)2 + 2KI -----> PbI2 + 2KNO3
It produces Potassium nitrate and Lead iodide
nothing
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Potassium nitrate and a precipitate of Silver iodide are formed
Dissolve each of the silver nitrate and potassium iodide separately in water, then mix the two solutions slowly with stirring. Silver iodide will precipitate and can be separated by filtering it from the liquid.
The products are Mercury(II) iodide and Potassium nitrate
It produces Potassium nitrate and Lead iodide
silver nitrate and potassium iodide can be used.
Silver iodide (AgI), a precipitate insoluble in water, don't react with potassium nitrate.
Ag(NO3)(aq) + KI(aq) ---> K(NO3)(aq) + AgI(s)
nothing
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Potassium nitrate and a precipitate of Silver iodide are formed
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Dissolve each of the silver nitrate and potassium iodide separately in water, then mix the two solutions slowly with stirring. Silver iodide will precipitate and can be separated by filtering it from the liquid.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
A precipitate of Lead iodide and Potassium nitrate are formed