nothing
It produces Potassium nitrate and Lead iodide
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Potassium nitrate and a precipitate of Silver iodide are formed
A precipitate of Lead iodide and Potassium nitrate are formed
potassium nitrate would be left was an aqueous solution and lead iodide would be the precipitate
It produces Potassium nitrate and Lead iodide
Silver iodide (AgI), a precipitate insoluble in water, don't react with potassium nitrate.
Ag(NO3)(aq) + KI(aq) ---> K(NO3)(aq) + AgI(s)
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
The products are Mercury(II) iodide and Potassium nitrate
Potassium nitrate and a precipitate of Silver iodide are formed
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
A precipitate of Lead iodide and Potassium nitrate are formed
Lead iodide (Pb2I) precipitates as a yellow solid, leaving a solution of potassium and nitrate ions.
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
2KI+Pb(NO(3))(2) yields 2KNO(3)+PbI(2). You basically get potassium nitrate and lead (II) iodide when you react potassium iodide and lead nitrate dissolved in solution.