The amount of a liquid that is displaced by a solid = the volume of that solid. You could half fill a graduated cylinder. Drop something that sinks into the graduated cylinder to test its volume.
depends on where i have missed the displaced volume..............could be anywhere...
Mass will determine how much water is displaced by something that floats. Volume will determine how much water is displaced by something that does not (that sinks).
density is mass per volume. First weigh (mass) the key, then to find it's volume, place it into a container with liquid and measure how much volume is displaced.
The water displaced by the stone is directly proportional to its volume
volume after anchor was in water minus volume of water without anchor in it = the volume of the anchor
volume in litres is equal to its weight in kgs 1000ltrs is equal to 1000kgs
Displaced water method.
Archimedes' principle is used. Water will be displaced by the volume of what is put into it. That displaced volume can be measured giving the weight.
Put the object in a bath of water and see what volume of water is displaced.
If you push it down, you can measure the volume of the displaced liquid.
Buoyant force is equal to the weight of the volume of water displaced. Buoyant force = [density of water] x [volume of water displaced] x [gravity]
You can find the displaced volume well, i think so im not sure if it's correct or not sorry!!
To find the mass of an object based on the displaced water, you can make use of Archimedes' principle. Measure the volume of the water displaced by the object, and then multiply it by the density of water (usually 1 g/mL). This will give you the mass of the object.
Measure the amount of liquid that is displaced by the object in question (you will probably need a graduated cylinder). The amount of liquid displaced is the volume of the object. Then, since you have the volume of the object, you can find the mass of the object. Mass=Density x Volume.
Push it down, and measure the displaced liquid.
Subtract the initial from the final
Length times Width times Height. Archimedes used a "bathtub", and submerged the object to see what volume of water was displaced.
Length times Width times Height. Archimedes used a "bathtub", and submerged the object to see what volume of water was displaced.