You can NOT
To neutralize acetic acid, you need a 1:1 molar ratio of calcium carbonate to acetic acid. The molar mass of acetic acid is 60.05 g/mol, so 0.83 mmol is 0.83 * 10^-3 mol. This requires 0.83 * 10^-3 mol of calcium carbonate, which is 0.83 * 10^-3 mol * 1000 mg/mol = 0.83 mg of calcium carbonate. In 250 mg tablets, you would need 0.83 mg / 250 mg = 0.00332 tablets, so you would need at least 1 tablet to neutralize the acetic acid in the quart of vinegar.
The chemical equation for the reaction between magnesium carbonate (MgCO3) and acetic acid (CH3COOH) is: MgCO3 + 2CH3COOH → Mg(CH3COO)2 + H2O + CO2
METAL REACTS WITH CARBOXYLIC ACID BY REPLACING THE HYDROGEN WHICH IS ATTACHED TO THE OXYGEN ...FOR EXAMPLE: Na REACTS WITH ACETIC ACID Na+CH3COOH=CH3COONa however in the case of divalent metals for examle Mg the equation will b like Mg+2(CH3COOH)=Mg(CH3COO)2
One quarter of a gram. One gram equals 1,000 Milligrams.
250 mg = 0.25 g
250 mg = 0.008818 ounces
250 mg/1 g = 250 mg/1000 mg = 250/1000 = 0.25 or 1/4
Zero unless you put it there or the manuracturer did. Vinegar is just acetic acid (CH3COOH) by another name and as you can see by the previous formula, there is no sodium (Na) in it.
248.5 mg
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It would be: 2HC2H3O2 + Mg -------> Mg (C2H3O2)2 + H2
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