To calculate the wasted energy in a TV, you would multiply the power consumption of the TV (in watts) by the time the TV is left on (in hours). This will give you the energy consumed in watt-hours (Wh). To convert watt-hours to joules, multiply by 3600 (since 1 Wh = 3600 joules).
Yes, both work and energy are measured in joules (J). Work is the transfer of energy, and both are quantified using the same unit.
The total energy added to the system is 160 Joules, comprising of 100 Joules of heat and 60 Joules of work. This increase in energy will lead to a rise in the system's internal energy.
Work and energy are typically measured in joules (J).
Various forms of energy can be measured in joules, such as kinetic energy, potential energy, heat energy, and electrical energy. Joules are a unit of measurement for energy and can be used to quantify the amount of energy present in a system or the amount of work done.
Work, or energy? The input energy is only going to be 70% of the capability of the devices' energy consumption. I believe that what is really desired here, but the structure of the question does not give this quantity, is how much loss due to inefficiency, or resistance in the machine for a given amount of input energy. The basic answer is 2150 Joules. Energy is what is available to the machine, but energy is only drawn as a result of the draw on the energy source driving the machine. To illustrate, a clothes dryer is capable of drawing 5000 watts of electrical power. Does it draw all of that power in watts every time it is turned on? No, of course not. If the dryer is set for a cycle such as air fluffing, then all the dryer will draw is enough energy in watts to make the drum turn. That is not going to anywhere near the rated 5000 watts the dryer is capable of demanding from it's power source. So, the question given is misleading. You can not put 7500 Joules of energy into a device, and make it use that amount of energy. The machine will only use what it needs to do the job it is to do, plus what it needs to over come frictional losses. Work is never lost, work is a function of what the machine does, for a given load, and it's ability to do the job asked of it. Proper use of terms leads to correct answers, while not using proper terms leads to confusion.
Both energy and work are measured in joules.
Yes, both work and energy are measured in joules (J). Work is the transfer of energy, and both are quantified using the same unit.
The total energy added to the system is 160 Joules, comprising of 100 Joules of heat and 60 Joules of work. This increase in energy will lead to a rise in the system's internal energy.
Work and energy are typically measured in joules (J).
Work is energy, measured in joules. The rate of work, or joules per second, is known as watts, or power.
Energy is the ability to do work. It is measured in joules.
Energy is the ability to do work . It is measured in Joules.
Various forms of energy can be measured in joules, such as kinetic energy, potential energy, heat energy, and electrical energy. Joules are a unit of measurement for energy and can be used to quantify the amount of energy present in a system or the amount of work done.
Yes, but it might be confusing to some, because it is also the unit for work. To do 100 joules of work, you need 100 joules of energy. See related link for more detail.
Work, or energy? The input energy is only going to be 70% of the capability of the devices' energy consumption. I believe that what is really desired here, but the structure of the question does not give this quantity, is how much loss due to inefficiency, or resistance in the machine for a given amount of input energy. The basic answer is 2150 Joules. Energy is what is available to the machine, but energy is only drawn as a result of the draw on the energy source driving the machine. To illustrate, a clothes dryer is capable of drawing 5000 watts of electrical power. Does it draw all of that power in watts every time it is turned on? No, of course not. If the dryer is set for a cycle such as air fluffing, then all the dryer will draw is enough energy in watts to make the drum turn. That is not going to anywhere near the rated 5000 watts the dryer is capable of demanding from it's power source. So, the question given is misleading. You can not put 7500 Joules of energy into a device, and make it use that amount of energy. The machine will only use what it needs to do the job it is to do, plus what it needs to over come frictional losses. Work is never lost, work is a function of what the machine does, for a given load, and it's ability to do the job asked of it. Proper use of terms leads to correct answers, while not using proper terms leads to confusion.
Work is energy, measured in joules. The rate of work, or joules per second, is known as watts, or power.
If you mean work as in energy it is joules (j).