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Work, or energy? The input energy is only going to be 70% of the capability of the devices' energy consumption. I believe that what is really desired here, but the structure of the question does not give this quantity, is how much loss due to inefficiency, or resistance in the machine for a given amount of input energy. The basic answer is 2150 Joules. Energy is what is available to the machine, but energy is only drawn as a result of the draw on the energy source driving the machine. To illustrate, a clothes dryer is capable of drawing 5000 watts of electrical power. Does it draw all of that power in watts every time it is turned on? No, of course not. If the dryer is set for a cycle such as air fluffing, then all the dryer will draw is enough energy in watts to make the drum turn. That is not going to anywhere near the rated 5000 watts the dryer is capable of demanding from it's power source. So, the question given is misleading. You can not put 7500 Joules of energy into a device, and make it use that amount of energy. The machine will only use what it needs to do the job it is to do, plus what it needs to over come frictional losses. Work is never lost, work is a function of what the machine does, for a given load, and it's ability to do the job asked of it. Proper use of terms leads to correct answers, while not using proper terms leads to confusion.

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Q: How much work is wasted if a machine with an input of 7500Joules only works at 70 percent efficiency?
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