frequency divided by speed i think
divide something by something
In the work function equation, the work function is the minimum energy needed to remove an electron from a material. The relationship between the work function, wavelength, and energy of a photon is that the energy of a photon is directly proportional to its frequency, which is inversely proportional to its wavelength. This means that a photon with higher energy (shorter wavelength) can provide enough energy to overcome the work function and eject an electron from the material.
Yes, a "black light" is an ultraviolet light with wavelength of about 395-410 nm.
v = fλ V/f = λ (wavelength) V = 340ms-1 340/f = λ In short you need to know the frequency of the particular sound wave to work out it's wavelength. once you know that you plug it into the above equation and you will get the wavelength of the wave.
Frequency and wavelength have an inverse relationship: as frequency increases, wavelength decreases, and vice versa. This means that shorter wavelengths correspond to higher frequencies and longer wavelengths correspond to lower frequencies. This relationship is described by the formula: frequency = speed of light / wavelength.
Both have something to do with lightThanks for that, and go to your room now.When the frequency is multiplied by the wavelength, the product isalways the same number ... 299,792,458 meters per second ... thespeed of light.
Wavelength and frequency are inversely proportional. The higher the frequency, the shorter (lower) the wavelength. Energy is proportional to frequency, and higher frequency waves will have a higher energy. Mathematically, frequency = 1 divided by wavelength, or f = 1/λ Use the link below for more information, including a diagram or two to make things clearer.
It's the distance between any consecutive crests or troughs . it is the length of a wave .
What Wavelength
An electrodynamometer can work as a voltmeter by judging the wavelength and force of the electricity, much the same at the voltmeter, then converting it to a force that is more recognizable.
Yes, definitely . For the given metal of particular work function, decrease in wavelength of the incident beam increases the maximum value of kinetic energy with which the photoelectrons are emitted, but the photoelectric current remains the same, stoppage voltage increases.
That would be what we call "radio" waves.Although, to the extent that there is E&M radiation from ordinary utility transmission lines, that would have a wavelength much longer than any radio communication. 60 Hz corresponds to a wavelength of something like 3,100 miles !