2 x 2 x 2 x 11 = 88
2 x 2 x 2 x 11 = 88
It is: 2*2*2*11 = 88
2 x 2 x 2 x 11 = 88
The prime factors of 88 are 2 x 2 x 2 x 11.Its prime factors are 2 and 11
Prime factor of 88 = 2x2x2x11The prime factorisation of 88 is 2 x 2 x 2 x 11, or alternatively 2^3 x 11.88 = 2 x 2 x 2 x 11
2 x 2 x 2 x 11 = 88
88=23x11 or 88=2x2x2x11
88 = 2 x 2 x 2 x 11 OR 23 x 11
It is: 2*2*2*11 = 88
The prime factors of 88 are 2 x 2 x 2 x 11
2 x 2 x 2 x 11 = 88
No because 88 as a product of its prime factors with exponents is: 23*11 = 88 which is the same as 2*2*2*11 = 88
To find the hcf of three numbers you first need to write them as the product of their prime factors: 11 = 11 88 = 2x2x2x11 44 = 2x2x11 The next step is to identify any common prime factors. In this case, all three numbers have a prime factor of 11. Therefore the hcf of 11, 88 and 44 is 11.
The prime factors of 88 are 2 and 11
2 x 2 x 2 x 11
The prime factors of 88 are 2 x 2 x 2 x 11.Its prime factors are 2 and 11
Prime factors are the combination of prime numbers which multiply to give the given integer exactly.If you begin by finding the lowest prime factor of your given number, and then divide by this and find the lowest prime factor of the result (and repeat until finished), you will see that for 88 we get:2 * 2 * 2 * 11. We write this as 2^3 * 11.2 x 2 x 2 x 11 = 88