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Write a program to find the reverse of a given number with help of function?
Wiki User
∙ 14y ago
//Reverse of the Number
#include<stdio.h>
#include<conio.h>
int main ()
{
int num,mod,rev=0;
printf("Enter a number:");
scanf("%d", &num);
while (num>0)
{
mod=num%10;
rev=(rev*10)+mod;
num=num/10;
}
printf("Reverse of the given number: %d", rev);
getchar();
return 0;
}
// alternative solution based on reversing the alphanumeric representation of
// the number:
void rev(int me) {
char alpha[32];
sprintf(alpha, "%d", me);
for (const char* cp = alpha + strlen(alpha) - 1; cp >= alpha; --cp) {
putchar(cp); }
}
Wiki User
∙ 11y ago
Wiki User
∙ 14y agosuppose you are given the number
9254
In order to reverse it, you must eliminate each value and reverse it.
For example,
9254 / 1000 = 9
9254 % 1000 = 254
then
254 / 100 = 2
254 % 100 = 54
then
54 / 10 = 5
54 % 10 = 4
and your final digit is 4.
I will leave it up to you to figure out how to implement this, but that is the algorithm for extracting digits.
It should be clear how to use loops to abstract this problem into a "reverse" function.
Wiki User
∙ 9y ago#include
Main()
{
Int num,r,rev=0;
Printf("enter a number");
Scanf("%d",&num);
While(num>0)
{
r=num%10;
rev=rev*10+r
num=num/10;
}
Printf("%d",rev);
}
Wiki User
∙ 11y ago#include <stdio.h>
void main() //Defining main function
{
int number, modulus, reverse; //Integer Declaration
reverse = 0; //Initialization
printf("Enter a number \n");
scanf("%d", &number);
while(number != 0)
{
modulus = number % 10;
reverse = (reverse * 10) + modulus;
number =number / 10;
}
printf("The reversed number is %d", reverse);
getch();
}
Wiki User
∙ 11y ago/*C Program to Enter 5 Number at a time & Display them in Reverse Order of the input*/
#include<stdio.h>
#include<conio.h>
void main()
{
int i, x[5];
clrscr();
for (i=0;i<5;i++)
{
printf("Enter the number\n");
scanf("%d",&x[i]);
}
printf("\nThe reverse order is\n");
for (i=4;i>=0;i--)
{
printf("\n%d",x[i]);
}
getch();
}
Wiki User
∙ 15y ago1. Convert the number to a string.
2. Reverse the characters
3. Drop any leading zeros on the new string
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