How do you write a c plus plus program to print aaaa aaab aabb abbb bbbb?

Answer 1

#include<iostream>

#include<string>

#include<algorithm>

bool compare_no_case (const char a, const char b)

{

return tolower(a) < towlower (b);

}

int main()

{

std::string s {"This is the string to be sorted!"};

std::cout << "Unsorted:\t"" << s << ""\n";

std::sort (s.begin(), s.end(), compare_no_case);

std::cout << "Sorted\t:"" << s << ""\n";

}

Answer 2

#include<iostream.h>

#include<conio.h>

void main()

{

int i;

char j;

clrscr();

for(i=97;i<102;i++)

{

for(j=97;j<=i;j++)

{

cout<<j;

}

cout<<endl;

}

getch();

}

Answer 3

#include
using namespace std;

int reverse(int input);

int main() {

cout << reverse(1234) << endl;

}

int reverse(int input) {

int output = 0;

while(input != 0) {

output = output * 10 + input % 10;

input /= 10;

}

return output;

}

Answer 4

for (char c='a'; c<='z'; ++c) std::cout << c;

for (char c='A'; c<='Z'; ++c) std::cout << c;

Answer 5

#include<iostream>

int main()

{ std::cout<<"a b a b c b a b c ....................."<<std::endl;

}

Answer 6

std::string s {"aaaa"};

for (int i=0; i<5; ++i) {

std::cout << s << " ";

s.pop.back();

s.append ('b');

}

Answer 7

std::string s {"abcde"};

while (!s.empty()) {

std::cout << s << " ";

s.pop_back();

}