#include<stdio.h>
int main () {
int odd=1;
int count=0;
while (count++<10) {
printf (%d\n", odd);
odd+=2;
}
return 0;
}
You write a loop, and use the counter variable. A forloop is very appropriate in this case. The System.out.println(...) method is appropriate for printing.
It is very easy. The program begins here..... /*Program to sum and print numbers without creating variables*/ #include<stdio.h> main() { clrscr(); printf("%d+%d=%d",5,2,5+2); getch(); } /*Program ends here*/ Now just by changing the numbers in the "printf" statement we can add, subtract, multiply and divide the numbers without using variables. Hence the problem is solved..........
unsigned count = 0;unsigned num=1; do { std::cout << num << std::endl; num +=2; } while (++count<50);
sdfdg
a triangle then a square :)
you need strings to print any character(your name) this is not possible useing array:D
Use the option File / Print in the program you are using.
It is very easy. The program begins here..... /*Program to sum and print numbers without creating variables*/ #include<stdio.h> main() { clrscr(); printf("%d+%d=%d",5,2,5+2); getch(); } /*Program ends here*/ Now just by changing the numbers in the "printf" statement we can add, subtract, multiply and divide the numbers without using variables. Hence the problem is solved..........
-- Photocopy the question or print the screen. -- Trim and discard the first 8.
USING STRING LITERAL VALUES TO ADD 2 NUMBERS If you just want to show the outcome of two numbers you have: PRINT 4 + 5 This will print '9' the answer to 4 + 5. If you want to show the addition: PRINT "4 + 5 = "; 4 + 5 This will show the question and then calculate the answer. If you want the user to input numbers to add, use variables and then add them the same way. ====== COLLECTING USER INPUT FROM THE KEYBOARD/USING NUMERIC VARIABLES In the following example, the end user can get to interact with the program by typing in their numbers at the keyboard; then, pressing the [Enter] key. CLS PRINT "PROGRAM: Add 2 numbers" PRINT INPUT "Enter the 1st number: ", number1 INPUT "Enter the 2nd number: ", number2 PRINT sumTotal=number1+number2 PRINT "The sum total is: "; sumTotal PRINT INPUT "Again, Y/N"; yesNo$ IF UCASE$(LEFT$(yesNo$,1))="Y" THEN RUN END ====== CREATE FUNCTION/THEN, MAKE A FUNCTION CALL TO ADD 2 NUMBERS Another way to write this program is to create a function/then, make a function call... '*** PROGRAM: Add 2 numbers... '*** Variable declaration list... number1=7 '...initialise numeric variable 1 number2=3 '...initialise numeric variable 2 '*** Main program... CLS '...(CL)ear the (S)creen PRINT add(number1,number2) '...make function call/passing in 2 numbers to add END '...END of program/halt program code execution '*** Function(s)... FUNCTION add(num1,num2) '...this line marks the start of the Function add=num1+num2 '...this line returns the sum total of the 2 numbers END FUNCTION '...this line marks the end of the Function
program to find maximum of two numbers using pointers
hi question is here, 1 1 2 1 2 3 1 2 3 4
A program which is used to count the number of numbers in an array using a 8085 microprocessor is known as a assembly language program.
sdfdg
unsigned count = 0;unsigned num=1; do { std::cout << num << std::endl; num +=2; } while (++count<50);
N = x If y < N then N = Y If z < N then N = z Print N
a triangle then a square :)
With printf.Example:for (i=0; i