Write a program that reads in five integer and then determines and prints the largest and the smallest integers in the group?

Answer 1

#include ; using namespace std; int main () { int number1 = 0; int number2 = 0; int number3 = 0; int number4 = 0; int number5 = 0; coutnumber2>>number3>>number4>>number5; {if (number1 > number2) if (number1 > number3) if (number1 > number4) if (number1 > number5) cout

Answer 2

#include <iostream>

#include <cstdlib>

using namespace std;

int generatehighvalue (int trials);

void countoccurrence(int trials);

void main ()

{

int highestgenerated;

highestgenerated = generatehighvalue(1000);

cout <<"difference we got is"<<RAND_MAX - highestgenerated<<endl;

cout<<"hishest possible is"<<RAND_MAX<< "and highest generated is"<<highestgenerated<<endl;

countoccurence(1);

}

]

int generatehighvalue (int valuetrials)

[

int num, compare;

num = rand();

compare = 0;

if (trials > 1)

compare = generatehighvalue(trials - 1)

if (compare > num)

return compare;

else

return num;

]

void countoccurence(int maxinum)

[

int occurence[128];

memset (occurence,0,sizeof(occurence));

if (maxnum > 128)

{

cout <<"<strong class="highlight">max</strong> <strong class="highlight">number</strong> cannot be more than 128"<<endl;

return ;

}

for(int trials = RAND_MAX; trials>0; trials--)

{

Answer 3

To find the minimum (or maximum) in any set of n numbers, assume that the first number is the minimum (or maximum) and then compare it with all the remaining numbers. If any number is less than (or more than) this number, then compare the remaining numbers with that number instead. When you've compared the entire set of numbers, you will have found the minimum (or maximum) in the set.

The following is an example using arrays of type int:

int min(int a[], size_t size)

{

size_t min=0, index=0;

while(++index<size)

if( a[index]<a[min] )

min=index;

return( a[min] );

}

int max(int a[], size_t size)

{

size_t max=0, index=0;

while(++index<size)

if( a[max]<a[index] )

max=index;

return( a[max] );

}

Answer 4

Let a, b, c be your three numbers. Then the required if-else condition statement is:

if( a>b && a>c)

printf("a is greatest");

else if( b>c && b>a)

printf("b is greatest");

else

printf("c is greatest");