This can be easily done using the modulo operation (represented by the '%' symbol). This operation gives the remainder of the division of the two numbers used in it.
e.g. 4 % 2 = 0, 5 % 2 = 1, 10 % 3 = 1, 10 % 2 = 0
In a modulo operation, any even number divided by 2 will always have a remainder of 0. This can be done in Python for a number range like so:
current_number = 1 # variable to store the current number being checked
while current_number <= 100: # loop to go through the range of numbers up until 10
if current_number % 2 == 0: # check if the current number has a remainder of 0
print(current_number) # if it does, then print it out
current_number += 1 # move to the next number
This will print out all the even numbers up until 100, each on a separate line.
this is the code for making a random number using python: import random >>>random.randint (1, 10) you can do whatever numbers you want.
It is very easy. The program begins here..... /*Program to sum and print numbers without creating variables*/ #include<stdio.h> main() { clrscr(); printf("%d+%d=%d",5,2,5+2); getch(); } /*Program ends here*/ Now just by changing the numbers in the "printf" statement we can add, subtract, multiply and divide the numbers without using variables. Hence the problem is solved..........
Sure! Here's a simple Python program that allows the user to input 5 numbers and then calculates and prints their total: numbers = [] for i in range(5): num = int(input("Enter a number: ")) numbers.append(num) total = sum(numbers) print("The total is:", total) This program prompts the user to enter a number 5 times, converts each input to an integer, stores them in a list, calculates the sum of the numbers using the sum() function, and finally prints the total.
It is actually quite easy to write a program in java to do this. The easiest way to do this that I can think of is to use the remainder operator (%) to test whether a number is odd or not. Here is a simple program that will print out all the odd numbers between 1 and 50. public class OddNumbers { public static void main(String[] args) { int i=1; while(i < 50) { if(i%2 != 0) { System.out.println(i); } i++; } } }
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//program to find the factorial value f any number using while loop #include<stdio.h> void main() { int i,n,fact=1; printf("Enter the number\n"); scanf("%d",&n); i=n; while (i>=1) { fact=fact*i; i--; } printf("The factorial value=%d",fact); } the above is a program for calculating tha factorial value of any number which is entered by the user
This program checks whether a number is odd or even. NOTE: This site removes formatting from answers. Replace (tab) with a tab or four spaces. #!/usr/bin/python print("Type a number.") n = input(": ") l = len(n)-1 even = ("02468") if n[l] in even: (tab)print(n, "is even.") if n[l] not in even: (tab)print(n, "is odd.")
Use the option File / Print in the program you are using.
this is the code for making a random number using python: import random >>>random.randint (1, 10) you can do whatever numbers you want.
It is very easy. The program begins here..... /*Program to sum and print numbers without creating variables*/ #include<stdio.h> main() { clrscr(); printf("%d+%d=%d",5,2,5+2); getch(); } /*Program ends here*/ Now just by changing the numbers in the "printf" statement we can add, subtract, multiply and divide the numbers without using variables. Hence the problem is solved..........
Here's the code for your program: # Loop through the uppercase alphabet letters for letter in range(ord('A'), ord('Z') + 1): print(chr(letter)) BTW you can use this code in Python and try it out for yourself.
program to find maximum of two numbers using pointers
USING STRING LITERAL VALUES TO ADD 2 NUMBERS If you just want to show the outcome of two numbers you have: PRINT 4 + 5 This will print '9' the answer to 4 + 5. If you want to show the addition: PRINT "4 + 5 = "; 4 + 5 This will show the question and then calculate the answer. If you want the user to input numbers to add, use variables and then add them the same way. ====== COLLECTING USER INPUT FROM THE KEYBOARD/USING NUMERIC VARIABLES In the following example, the end user can get to interact with the program by typing in their numbers at the keyboard; then, pressing the [Enter] key. CLS PRINT "PROGRAM: Add 2 numbers" PRINT INPUT "Enter the 1st number: ", number1 INPUT "Enter the 2nd number: ", number2 PRINT sumTotal=number1+number2 PRINT "The sum total is: "; sumTotal PRINT INPUT "Again, Y/N"; yesNo$ IF UCASE$(LEFT$(yesNo$,1))="Y" THEN RUN END ====== CREATE FUNCTION/THEN, MAKE A FUNCTION CALL TO ADD 2 NUMBERS Another way to write this program is to create a function/then, make a function call... '*** PROGRAM: Add 2 numbers... '*** Variable declaration list... number1=7 '...initialise numeric variable 1 number2=3 '...initialise numeric variable 2 '*** Main program... CLS '...(CL)ear the (S)creen PRINT add(number1,number2) '...make function call/passing in 2 numbers to add END '...END of program/halt program code execution '*** Function(s)... FUNCTION add(num1,num2) '...this line marks the start of the Function add=num1+num2 '...this line returns the sum total of the 2 numbers END FUNCTION '...this line marks the end of the Function
hi question is here, 1 1 2 1 2 3 1 2 3 4
Sure! Here's a simple Python program that allows the user to input 5 numbers and then calculates and prints their total: numbers = [] for i in range(5): num = int(input("Enter a number: ")) numbers.append(num) total = sum(numbers) print("The total is:", total) This program prompts the user to enter a number 5 times, converts each input to an integer, stores them in a list, calculates the sum of the numbers using the sum() function, and finally prints the total.
A program which is used to count the number of numbers in an array using a 8085 microprocessor is known as a assembly language program.
It is actually quite easy to write a program in java to do this. The easiest way to do this that I can think of is to use the remainder operator (%) to test whether a number is odd or not. Here is a simple program that will print out all the odd numbers between 1 and 50. public class OddNumbers { public static void main(String[] args) { int i=1; while(i < 50) { if(i%2 != 0) { System.out.println(i); } i++; } } }