Let (x1, y1) = (-4, -2) and (x2, y2) = (4, 2), then the slope m of the line is:
m = (y2 - y1)/(x2 - x1) = [2 - (-2)]/[4 - (-4)] = (2 + 2)/(4 + 4) = 4/8 = 1/2
Write the point-slope form of the equation of a line by using the slope m = 1/2 and the point (4, 2):
(y - y2) = m(x - x2) substitute what you know into the equation
(y - 2) = (1/2)(x - 4)
y - 2 = (1/2)x - 2 subtract (1/2)x and add 2 to both sides
y - (1/2)x = 0 multiply by -1 to both sides and interchange the places of the terms
(1/2)x - y = 0
Thus, the standard form (Ax + By = C) is (1/2)x - y = 0.
The standard form is: 5x - y + 4 = 0
readuse the answer
To be able to write the equation of a line in standard form. In particular, our book would not have cleared the fraction.
It is: 8.0*10^-4 in standard form or scientific notation
How do write 666 in standard form?
(3,1)(3,2)
I need step by step on my graphic calculator on how to write an equation
the formula for standard form is Ax+By=C
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
The standard form is: 5x - y + 4 = 0
readuse the answer
ax2 + bx + c
To be able to write the equation of a line in standard form. In particular, our book would not have cleared the fraction.
7x +y = 6
2X - y - 8 = 0the standard form of the equation is y = mx + chere you have to write the given equation in the standard form as in the form of y = mx + c2X - y - 8 = 0 - y -8 = -2x-y = -2x +8y = 2x -8so the standard form of the given equation is y = 2x - 8
Ex: 3x-4y=12
It is: 8.0*10^-4 in standard form or scientific notation