The unbalanced equation: Al + NaNO3 Becomes the balanced equation: Al + 3NaNO3 --> Al(NO3)3 + 3Na for Single Reaplacement.
Al starts at 0 oxidation. then becomes Al 3+ O remains -2 on both sides. H starts at 1+ then becomes 0
Al(MnO4)3 Al(MnO4)3
Aluminum must lose 3 electrons to satisfy the octet rule. Once it does this, it becomes the Al+3 ion, and is isoelectronic with noble gas neon.
Al(NO3)3 is aluminum nitrate.
Al or aluminum is atomic number 13. A soft white ductile metal.
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The molar mass of Al(CN)3 is 105.0337 g/mol. To determine the moles Al(CN)3 in 229 g Al(CN)3, multiply the given mass by 1 mol/105.0337 g.229 g Al(CN)3 x 1 mol Al(CN)3/105.0337 g Al(CN)3=2.18 mol Ag(NO)3, rounded to 3 significant figures
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is Al(C2H3O2)3 ionic or covalent
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Al(NO3)3(aq) ===> Al^3+(aq) + 3NO3^-(aq) is how aluminum nitrate ionizes in aqueous media.