A bromine atom with a mass number of 79 loses one electron to become a bromine ion with a negative 1 charge. This occurs when the atom gains an extra electron, giving it a full outer electron shell of 8 electrons, thus forming the Br- ion.
An atom of bromine-79 can become a bromide ion with a -1 charge by gaining an electron. Bromine-79 has 35 protons and 44 neutrons, making it electroneutral. By gaining an electron, it attains the electron configuration of a stable halide ion with 36 electrons, resulting in a net charge of -1.
The iconic charge of bromine is -1.
A bromine ion can have a charge of -1.
The oxidation number of bromine in KBr is -1. In ionic compounds, the oxidation number of the cation (K+) is always equal to its charge, which is +1. Therefore, the oxidation number of bromine must be -1 to balance the overall charge of the compound.
The formula of lead(II) bromide is PbBr2. Lead has a 2+ charge, while bromine has a 1- charge, so it takes two bromine atoms to balance out the charge on one lead atom.
An atom of bromine-79 can become a bromide ion with a -1 charge by gaining an electron. Bromine-79 has 35 protons and 44 neutrons, making it electroneutral. By gaining an electron, it attains the electron configuration of a stable halide ion with 36 electrons, resulting in a net charge of -1.
The iconic charge of bromine is -1.
A bromine ion can have a charge of -1.
-1
An atom of bromine-79 becomes a bromide ion with a -1 charge by gaining an extra electron. Bromine, which has seven valence electrons, needs one more to achieve a full outer shell and reach a stable electronic configuration. When it gains this additional electron, it becomes negatively charged, resulting in the bromide ion (Br⁻). This process is common among nonmetals, which tend to gain electrons to form anions.
Bromine on the periodic table is Br. 35 79.909
The charge of CoBr3 is 3+. This is because bromine (Br) typically has a charge of -1, and there are three bromine atoms in CoBr3. By setting the overall charge of the compound to zero, the cobalt (Co) ion must have a charge of 3+ to balance the charges of the bromine atoms.
A bromine ion has a -1 charge. That's because it is a halogen, and it is an electron "borrower" which wants to steal an electron to "complete" its outer electron shell. When it snags an electron to fulfill that tendancy of atoms to attain inert gas electron configuration, it ends up with that "extra" electron and a -1 charge. This is typical of all halogens, those elements that make up the Group 17 elements.
The oxidation number of bromine in KBr is -1. In ionic compounds, the oxidation number of the cation (K+) is always equal to its charge, which is +1. Therefore, the oxidation number of bromine must be -1 to balance the overall charge of the compound.
The charge of KBr is 0, since it is a neutral compound made of potassium (K) with a +1 charge and bromine (Br) with a -1 charge.
The formula of lead(II) bromide is PbBr2. Lead has a 2+ charge, while bromine has a 1- charge, so it takes two bromine atoms to balance out the charge on one lead atom.
The compound formed from cesium and bromine is cesium bromide, with the chemical formula CsBr. It is an ionic compound where cesium contributes a +1 charge and bromine contributes a -1 charge to form a balanced compound.