The charge of KBr is 0, since it is a neutral compound made of potassium (K) with a +1 charge and bromine (Br) with a -1 charge.
KBr (potassium bromide) is a neutral compound, so it does not have a charge. The potassium ion (K+) has a charge of +1, while the bromide ion (Br-) has a charge of -1. When combined in a 1:1 ratio to form KBr, the charges balance out to give an overall neutral compound.
The binary name for KBr is Potassium Bromide.
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KBr is transparent to IR radiation, most alkali halides are transparent in ir
KBr (potassium bromide) is a neutral compound, so it does not have a charge. The potassium ion (K+) has a charge of +1, while the bromide ion (Br-) has a charge of -1. When combined in a 1:1 ratio to form KBr, the charges balance out to give an overall neutral compound.
The oxidation number of bromine in KBr is -1. In ionic compounds, the oxidation number of the cation (K+) is always equal to its charge, which is +1. Therefore, the oxidation number of bromine must be -1 to balance the overall charge of the compound.
To prepare a 0.01N KBr solution, dissolve 0.74g of KBr in 1 liter of water. This will give you a solution with a molarity of 0.01N for KBr.
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The bromide ion has a charge of -1. In the ionic compound potassium bromide (KBr), potassium has a charge of +1 to balance the -1 charge of the bromide ion.
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The binary name for KBr is Potassium Bromide.
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KBr is Potassium Bromide
Yes, potassium bromide (KBr) is soluble in water. It forms a clear, colorless solution when dissolved.
To find the number of moles in 22.23 g of KBr, we need to divide the given mass by the molar mass of KBr. The molar mass of KBr is 119 g/mol. Therefore, 22.23 g of KBr is equal to 0.187 moles.