Since the volume of a container is generally understood to be the capacity of the container, i. e. the amount of fluid (gas or liquid) that the container could hold, rather than the amount of space the container itself displaces.If the volume were measured by displacement of such water, there would be no effect on the density of the solid. But the measurement would be inaccurate, leading to a misrepresentation of the actual density.
Density = (mass)/(volume)
Assume that the mass had been accurately measured by other means, and the volume then measured by displacement of water that included air bubbles.
During the overflow procedure, the air would escape, and only the H2O component of the displaced fluid would be available for measurement. Hence, the volume of the solid would be under-reported.
Since (volume) is the denominator of the fraction, the apparently smaller volume would cause the quantity (mass)/(volume) to become artificially large, and the density of the solid would appear larger than its actual density.
--relxerd
In the water displacement method, the object MUST be completely submerged in the water. If it isn't, only the volume of the submerged portion will displace the water and the portion floating above the level of water can not be measured.
If there are air bubbles present in the water during a water displacement, the density of a solid is lower than its actual density. This is because the air bubbles will tend to increase the measured volume. Since density and volume are indirectly proportional, an increase in volume will decrease the density.
Air bubbles don't affect the density of a solid. But if there are air bubbles
in a sample of the solid, then its density APPEARS to be less, because in
some of the places where you think there's solid, there's only air.
If the volume were measured by displacement of such water, there would be no effect on the density of the solid. But the measurement would be inaccurate, leading to a misrepresentation of the actual density. Density = (mass)/(volume) Assume that the mass had been accurately measured by other means, and the volume then measured by displacement of water that included air bubbles. During the overflow procedure, the air would escape, and only the H2O component of the displaced fluid would be available for measurement. Hence, the volume of the solid would be under-reported. Since (volume) is the denominator of the fraction, the apparently smaller volume would cause the quantity (mass)/(volume) to become artificially large, and the density of the solid would appear larger than its actual density.
It would lighten the density, but the air would float to the top and disperse.
What would be the effect on the density of a solid whose volume was determined by water displacement if air bubbles were present in the water?
Properly calculated, the density should incorporate the bubbles. If the bubbles were to "escape", the density would increase and need to be recalculated to be accurate.
dont cheat
as the altitude increase, the effect of gravity become more insignificant on air and the air become more disperse or thinner hence it does affect the air pressure and density by decreasing both air pressure and density of the air.
if it is high the density is high so if the temperature is low the density is low.
As the air bubble increases in volume, its mass remains constant. Because the mass remains constant but volume increases, density will decrease.
It will increase the total volume, but it will hardly affect total mass. Remember the definition of density as mass / volume.
Bubbles are comprised of gases, which have a lesser density than water. Since they are less dense, they get pushed up to the surface, and they rise, lighter than the liquid around them.
they dont
The air bubbles lower the density of the solution
Altitude has a large affect on the air pressure and air density. Air density reduces with altitude and air pressure reduces with altitude as well.
Pressure affects the density of air by increase of pressure increases the density
thank you
as the altitude increase, the effect of gravity become more insignificant on air and the air become more disperse or thinner hence it does affect the air pressure and density by decreasing both air pressure and density of the air.
bum hole
Air bubbles would make the volume you read in the measuring cylinder increase from the actual volume of theliquid. so when you add in the metal, there would be an increase in the volume of the metal than it really is. the mass of the metal cannot be affected by air bubble because this is the amount of matter in the metal. This increase in volume causes the density of the metal to reduce from its original value. since mass is constant, density is inversely proportional to volume. As volume increases, density decreases.hope that was helpful.
Air pressure affects buuble ,by... pushing through all the sides.This can affect the buuble. I wish there were a way to stop that!
Air pressure decreases as altitude increases. As air pressure decreases, so does density.
A bubbles is a liquid filled with air, therefore no it is not a solid :). Just liquid floating around. Reasons for why they go up and down an be because of the temperature. Hot air goes up cold air goes down. I'm not really sure but yeah there's a lot of interesting facts behind bubbles :) you could probably even make a solid bubble. but i don't think it would be as much fun as soap bubbles.
if it is high the density is high so if the temperature is low the density is low.