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Since the volume of a container is generally understood to be the capacity of the container, i. e. the amount of fluid (gas or liquid) that the container could hold, rather than the amount of space the container itself displaces.If the volume were measured by displacement of such water, there would be no effect on the density of the solid. But the measurement would be inaccurate, leading to a misrepresentation of the actual density.

Density = (mass)/(volume)

Assume that the mass had been accurately measured by other means, and the volume then measured by displacement of water that included air bubbles.

During the overflow procedure, the air would escape, and only the H2O component of the displaced fluid would be available for measurement. Hence, the volume of the solid would be under-reported.

Since (volume) is the denominator of the fraction, the apparently smaller volume would cause the quantity (mass)/(volume) to become artificially large, and the density of the solid would appear larger than its actual density.

--relxerd

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