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The atom loses 1 electron to have a total of 36.

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Wiki User

11y ago
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AnswerBot

2d ago

An atom of rubidium-85 becomes a rubidium ion with a 1 charge by losing one electron. Since rubidium-85 has 37 protons and 37 electrons, losing one electron would result in the ion having 37 protons and 36 electrons, giving it a net charge of +1.

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Q: How does an atom of rubidium-85 become a rubidium ion with a 1 charge?
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