It shouldn't affect the speed much, but at different angles (and the same speed), an object can reach different distances.
Hello: * Yes, the angle of a catapult does affect the distance. And this applies to both changing the angle of the catapult and changing the angle of the terrain under the catapult. If you shoot the catapult at say 45 degrees, you have very good distance. If you shoot it at 30 degrees, while it may be further, it would be lower to the ground and perhaps not travel as far hitting trees and running into wind-shear. If you shoot at say 80 degrees, while the lob goes high up in the air, it won't travel very far. So your best bet, for maximum distance, is to take your catapult to the highest possible altitude, aim for 45 degrees, taking into account the wind direction and speed, and lob away. Don't hit anyone. :) Answer Actually, the maximum distance that can be achieved from a catapult is at an angle of 45 degrees. Every degree increase from 0 up to 45 approaches the maximum distance that something can be thrown. Every degree from 45 to 90 decreases the distance.
By laws of physics, the angle at which something is launched into the air affects how far it will travel. Not taking into account air resistance, 45 degrees would be the ideal angle for maximum distance.
it will rather be possible for you not trying it
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Q: How do you think increasing a medium's index of refraction might affect the angle of refraction?
Hello: * Yes, the angle of a catapult does affect the distance. And this applies to both changing the angle of the catapult and changing the angle of the terrain under the catapult. If you shoot the catapult at say 45 degrees, you have very good distance. If you shoot it at 30 degrees, while it may be further, it would be lower to the ground and perhaps not travel as far hitting trees and running into wind-shear. If you shoot at say 80 degrees, while the lob goes high up in the air, it won't travel very far. So your best bet, for maximum distance, is to take your catapult to the highest possible altitude, aim for 45 degrees, taking into account the wind direction and speed, and lob away. Don't hit anyone. :) Answer Actually, the maximum distance that can be achieved from a catapult is at an angle of 45 degrees. Every degree increase from 0 up to 45 approaches the maximum distance that something can be thrown. Every degree from 45 to 90 decreases the distance.
True.
By laws of physics, the angle at which something is launched into the air affects how far it will travel. Not taking into account air resistance, 45 degrees would be the ideal angle for maximum distance.
45°
To achieve the most distance, you should set your catapult to release a projectile at 45 degrees angle relative to horizontal plane.Higher stored potential energy doesn't neccesarily mean more distance. Distance of the shot depends mainly on starting velocity, which in turn depends on rate at which catapult transfers the energy to the projectile. A limit for that depends on construction of the catapult.
A rotation turns a shape through an angle at a fixed point thus changing its coordinates
The distance an object can be fired from a catapult can be most easily changed by altering the height of the front of the catapult. Since the projectile's motion follows a parabolic arc, changing the initial trajectory should yield different distances. This is just like a gun, which only really fires at one particular muzzle velocity, but the distance can be changed based upon the angle at which a person fires.
Me!!
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some objects that has an obtuse angle is a pentagon, laptop and the objects that is greater than 90 degrees
Easy . Think of it like this. The higher you angle your catapult (or whatever your using.) The higher it will travel but it will have less power. If you have a lower angle you will have more power but it your projectile will hit the ground first. If you don't understand just play around with a slingshot and an empty can of soda. Or you could test it out this theory by playing around with angry birds ;)
The calculations for changing the firing angle in SCR is K = 1 [π − α + 1 sin(2α )]