The kinetic energy of the vehicle when it is travelling faster is four times as great. It the brakes apply the same retardation and the friction from the tires on the road surface is unchanged then the stopping time will be four times as long.
kinetic
The braking force x stopping distance (assuming constant braking force) is equal to the loss of kinetic energy of the vehicle.And if it's not constant, you can integrate the dot product of the force vector and the differential x-vector.If you want the power of heat generation, you will need to find how much energy is being dissipated (i.e. how much kinetic energy is lost) per unit of time.
The distance travelled is irrelevant; you need the speed. (Perhaps the problem states that the toy car travels so-and-so far in so-and-so much time; in this case, you can figure out the speed.) The formula for kinetic energy is: KE = (1/2)mv2, that is, 1/2 times the mass times the square of the speed.
If several objects have the same speed and the same velocity,then each has the same kinetic energy.
The kinetic energy of a falling object is directly proportional to the distance it falls.But the distance is not directly proportional to the time in fall, so the KE is not directly proportionalto the time either.
kinetic
Some of the kinetic energy of a body in motion is used up in overcoming friction, which acts in the direction opposite to that of the motion. The reduction in energy means that the stopping force needs less time to do its work.
kinetic energy
Tyre surface: If the tyre is new, it will have surface with depressions which will offer more friction compared to old tyre whose surface-depressions are worn out and it is more flat, so it offers less friction. Therefore, new tyre will have less stopping distance, as force of friction is more. Thinking distance is affected neither by friction between tyre and road, nor by friction between brake and tyre. If road has a wet surface, it has less friction so the vehicle will skid farther, and vice versa. The braking force, i.e, friction between tyre and brake is unaffected by road condition or tyre surface. Hence the distance the vehicle travels WHILE retarding due to "braking force", is not same as stopping distance, because even when the wheels are stopped rotating due to braking force, the car will skid a little distance- this total distance is the stopping distance.
Because kinetic energy KE ~ V^2 (varies as the square of the speed). So ke ~ v^2 and KE ~ V^2 and when V = 2v, doubled, we have KE/ke = (V/v)^2 = (2v/v)%2 = 4 so that KE = 4 ke. QED. The new kinetic energy is four times the old. And, ta da, that means there is four times as much energy for the brakes to sap and reduce to zero kinetic energy, which means V = 0 is the end speed (stopped). So by the work function, which you should know by now, we have WE = FS where F is the braking force (friction) and S is the stopping distance. We assume the braking force remains the same for both speeds. Then KE - WE = 0, meaning the kinetic energy is sapped by the work so there is none left. And we have KE = WE = FS; so S = WE/F = KE/F and the stopping distance varies as the kinetic energy. So when the speed is doubled and the kinetic energy is quadrupled, the stopping distance is quadrupled because there is now four times as much kinetic energy to expend in stopping. QED.
The kinetic energy of a 22500 lb truck traveling 55 mph is 1/2mv2 is 3084.808kJ.
The answer depends on what two (or more) things the ratio is meant to compare. The kinetic energy of several objects? The kinetic energy of an object compared to its total energy? The kinetic energy compared to its engine size?
Kinetic and potential energy are a type of energy, not a measurement of distance.
The bike's kinetic energy is 45 joules.
Kinetic energy also depends on mass.
Kinetic Energy
The kinetic energy in joules of an automobile weighing 2135 lb and traveling at 55 mph is 2.9 x 105.