How does potash alum react with sodium carbonate?

Answer 1

Hi there! I'm assuming that you are asking for what the reaction between phosphoric acid and sodium carbonate will yield right? Well if that's your question here are the steps to the solution:

1) Identify what kind of reaction this is. Since phosphoric acid is well....an acid and sodium carbonate is a base, the reaction type is an acid-base reaction. This means that the products generated by the reaction will be a salt(s), carbon dioxide, and water.

2) Figure out the formulas for your reactants and products. Your reactants, phosphoric acid and sodium carbonate, are H3PO4 and Na2CO3 respectively. From the previous step you already found two of your three products to be carbon dioxide (CO2) and water (H2O). Since the phosphate and sodium ions are left, they will form the salt sodium phosphate (Na3PO4).

3) Set up your preliminary, unbalanced equation:

H3PO4 + Na2CO3 -------> Na3PO4 + CO2 + H2O

4) Choose the most complicated reactant, in this case Na3PO4 and begin to balance each of its components on both sides. In order to balance the sodiums on both sides, multiply the Na2CO3 on the reactants side by 3 and on the products side by 2 to attain 6 sodiums on each side.

H3PO4 + 3Na2CO3 -------> 2Na3PO4 + CO2 + H2O

Since there are two phosphate ions on the products side in 2Na3PO4 there must be two on the reactants side as well. Therefore multiply the H3PO4 by 2:

2H3PO4 + 3Na2CO3 -------> 2Na3PO4 + CO2 + H2O

There are six hydrogen atoms on the reactants side, therefore the H2O on the products side must be multiplied by 3 to yield six hydrogen atoms:

2H3PO4 + 3Na2CO3 -------> 2Na3PO4 + CO2 + 3H2O

Lastly, there exist 3 carbon atoms on the reactants side in 3Na2CO3 therefore CO2 on the product side must be multiplied by 3 to maintain equilibrium.

2H3PO4 + 3Na2CO3 -------> 2Na3PO4 + 3CO2 + 3H2O

Although everything appears to be balanced at this point, it is still a good measure to check over the oxygens to see if their numbers match on both sides. There are 17 on the reactants side and 17 on the products side.

5) Therefore your final, balanced equation is:

2H3PO4 + 3Na2CO3 -------> 2Na3PO4 + 3CO2 + 3H2O

Answer 2

Na2Co3 + K2H2Sb2O7(potassium pyro antinoconate)--------------->K2CO3 +Na2H2Sb2O7(milkiness white ppt)

This may happen as Sodium Chloride shows following reaction with pottassium ptro antimonate

2NaCl + K2H2Sb2O7(potassium pyro antinoconate)------------------>2KCl +Na2H2Sb2O7(milkiness white ppt)

Answer 3

As both of these compounds are alkali, these two reagents do not react with each other.

Answer 4

The chemical reaction is:
Ca(NO3)2 + K2CO3 = CaCO3(s) + 2 KNO3