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They are the same factors affecting any other kind of force. If the centripetal force

is gravitational, then it depends on the masses of the two bodies involved and the

distance between them. If it's electrostatic, then it depends on their charges and

the distance between them. If it's the force that bends a car around a curve, then

it depends on the bank in the pavement and the coefficient of friction between the

road and the tires.

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11y ago
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16y ago

A force which pulls an object toward the center of a circle is called a centripetal force. How much centripetal force needs to be exerted to cause an object to move in a circle? Your experience should tell you that the amount of centripetal force that you need to exert depends on # the mass of the object you are whirling - heavier objects require more force, # how fast you are whirling it - going faster requires more force, and # the radius of the circle. The textbook says:

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15y ago

Well, you know that centripetal acceleration is velocity squared, divided by radius. And that force is mass times acceleration

ac=v2/r

F=ma

Sub the first into the second and you are left with

Fc=(mv2)/r

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11y ago

Centripetal force is the force toward the center of a curve that must be present in

order to move an object along the curved path.

Centrifugal force is the name given to the sensation we seem to feel of a force that

draws us away from the center when we move along a curved path. It is actually

imaginary; that is, it doesn't exist.

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13y ago

Centrepital force is not the same as gravity.

Centrepital force the the force exherted on a object travelling in a circular motion by whatever is holding it to the circular path to counter the object's intertia or resistance to change directions. In the example of a ball on a string, the ball at every moment wants to travel out in a line that is tangent to its current position in it's orbit. The string acts as an achor constantly overcoming the intertia and readjusting the ball's position to keep it on its orbit.

Centripetal force also varies with the object's mass and angular momentum. Whereas gravity is constant with an acceleration of -9.81 m/s2 for all objects regardless of mass.

Nice but i disagree , I think you are cutting hares so to speak. Gravity is gravity and scientists always want to divide what is plantantly obvious.Why divide a force that is prevalent in nature into little boxes. Look at nuclear physics there is no mimical forces happening there. gravity and sentrufeecal forces are the same thing your just splitting hares. Of course things must be compartmentalised in under to understand them but a prevalence to libravacation is just writing more books. I love scientist's but dont do that.

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10y ago

Higher mass means the object needs higher centripetal force

Higher mass means higher inertia so the object is more resistant to the acceleration by the centripetal force

Higher speed means the object needs higher centripetal force

Higher speed means lower friction (or air resistance) that means lower centripetal force is supplied and the object becomes more likely to move in a straight line and break the circular motion and we lose control over it. That's why we have to slow down when we take a u turn

Smaller radius means the object needs higher centripetal force

Smaller radius means a sharper turn and so the direction of the velocity is changing more frequently which means higher acceleration and that's why we need higher centripetal force

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8y ago

The relationship between mass and gravitational force evidenced is a consequence of intrinsic properties of matter and the fundamental forces of the universe. They are in direct proportion, more mass means greater total force. Newton's second law of motion indicates the product of the mass and acceleration is equal to the force. Newton's gravitational constant (G) can be used to calculate the value of the force between two objects of a known mass and separation.

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Q: How does radius speed mass affect centripetal force?
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How does speed affect centripetal force?

Force (newtons) = mass (kg) * acceleration ((m/s)/s) but > acceleration in a circle = velocity 2 / radius So > (centripetal) force = mass * (velocity 2 / radius)


How do you solve for revolutions per second give centripetal force and radius?

One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.


What is the net force directed to the center of an objects circular path?

That is called the centripetal force. Its magnitude is speed squared / radius.That is called the centripetal force. Its magnitude is speed squared / radius.That is called the centripetal force. Its magnitude is speed squared / radius.That is called the centripetal force. Its magnitude is speed squared / radius.


What will be the accelaration of a car moving in circle with uniform speed?

f=ma centripetal force= mvsquared/radius so centripetal acceleration=vsquared/radius


If the radius of rotation and the mass being kept constant how does the centripetal force vary with the speed of rotation of the body?

Recall centripetal force = m v^2 / rAs m and r are found to be constants then centripetal force F is directly proportional to the square of the velocity of the body

Related questions

How do they affect the centripetal force?

If an object moves in a circle, the centripetal acceleration can be calculated as speed squared divided by the radius. The centripetal force, of course, is calculated with Newton's Second Law: force = mass x acceleration. Therefore, the centripetal force will be equal to mass x speed2 / radius.


How does speed affect centripetal force?

Force (newtons) = mass (kg) * acceleration ((m/s)/s) but > acceleration in a circle = velocity 2 / radius So > (centripetal) force = mass * (velocity 2 / radius)


How do you solve for revolutions per second give centripetal force and radius?

One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.


What is the net force directed to the center of an objects circular path?

That is called the centripetal force. Its magnitude is speed squared / radius.That is called the centripetal force. Its magnitude is speed squared / radius.That is called the centripetal force. Its magnitude is speed squared / radius.That is called the centripetal force. Its magnitude is speed squared / radius.


How does centripetal force affect centripetal force?

Centripetal acceleration is proportional to the square of the speed (a = v2/r). Therefore, according to Newton's Second Law, centripetal force is also proportional to the square of the speed.


What will be the accelaration of a car moving in circle with uniform speed?

f=ma centripetal force= mvsquared/radius so centripetal acceleration=vsquared/radius


What is the formula in getting centripetal force and it's net horizontal force?

One formula for centripetal force is v2/2 - the square of the velocity (speed, actually) divided by the radius. Another is omega2r, where omega is the angular speed, in radians/second.One formula for centripetal force is v2/2 - the square of the velocity (speed, actually) divided by the radius. Another is omega2r, where omega is the angular speed, in radians/second.One formula for centripetal force is v2/2 - the square of the velocity (speed, actually) divided by the radius. Another is omega2r, where omega is the angular speed, in radians/second.One formula for centripetal force is v2/2 - the square of the velocity (speed, actually) divided by the radius. Another is omega2r, where omega is the angular speed, in radians/second.


What decreases the centripetal force?

If a body of mass m is in uniform circular motion with speed v and radius r, then the force acting on it has magnitude F = mv2 / r and is directed towards the centre of the circle. This is termed a "centripetal" (meaning "centre-seeking") force. To decrease the magnitude of the centripetal force, you must therefore either decrease the mass of the body, decrease the orbital speed, or increase the radius of the orbit.


If the radius of rotation and the mass being kept constant how does the centripetal force vary with the speed of rotation of the body?

Recall centripetal force = m v^2 / rAs m and r are found to be constants then centripetal force F is directly proportional to the square of the velocity of the body


How does the centripetal force with the speed of rotation of the body with constant mass and radius of rotation?

You can calculate the centripetal ACCELERATION with one of these formulae: acceleration = velocity squared / radius acceleration = omega squared x radius Acceleration refers to the magnitude of the acceleration; the direction is towards the center. Omega is the angular speed, in radians per second. To get the centripetal FORCE, you can use Newton's Second Law. In other words, just multiply the acceleration by the mass.


What is the relationship between centripetal force and speed?

centripetal force is the object moving in a circular orbit, speed is just how fast it does it


What is the centripetal force on a 4 kg moving at meter-SEC around a curve with a radius of 4 meters?

First, calculate the centripetal acceleration, as speed squared divided by radius.Then you can use Newton's Second Law to calculate the corresponding force.