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They are the same factors affecting any other kind of force. If the centripetal force

is gravitational, then it depends on the masses of the two bodies involved and the

distance between them. If it's electrostatic, then it depends on their charges and

the distance between them. If it's the force that bends a car around a curve, then

it depends on the bank in the pavement and the coefficient of friction between the

road and the tires.

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Factors that affect tha increase of centripetal force in uniform circular motion?

Centripetal force increases with an increase in the speed or radius of the circular motion. It is inversely proportional to the radius of the circle and directly proportional to the square of the velocity. Generally, any factor that increases the velocity or decreases the radius will increase the centripetal force.


How do you solve for revolutions per second give centripetal force and radius?

One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.


How does speed affect centripetal force?

Force (newtons) = mass (kg) * acceleration ((m/s)/s) but > acceleration in a circle = velocity 2 / radius So > (centripetal) force = mass * (velocity 2 / radius)


If the radius of rotation and the mass being kept constant how does centripetal force vary with the speed of rotation body?

Centripetal force is directly proportional to the square of the speed of rotation. As the speed of rotation increases, the centripetal force required to keep the object moving in a circular path also increases. This relationship follows the formula Fc = mv^2 / r, where Fc is the centripetal force, m is the mass, v is the speed, and r is the radius of rotation.


If the radius of rotation and the mass being kept constant how does the centripetal force vary with the speed of rotation of the body?

Recall centripetal force = m v^2 / rAs m and r are found to be constants then centripetal force F is directly proportional to the square of the velocity of the body

Related Questions

How do they affect the centripetal force?

If an object moves in a circle, the centripetal acceleration can be calculated as speed squared divided by the radius. The centripetal force, of course, is calculated with Newton's Second Law: force = mass x acceleration. Therefore, the centripetal force will be equal to mass x speed2 / radius.


Factors that affect tha increase of centripetal force in uniform circular motion?

Centripetal force increases with an increase in the speed or radius of the circular motion. It is inversely proportional to the radius of the circle and directly proportional to the square of the velocity. Generally, any factor that increases the velocity or decreases the radius will increase the centripetal force.


How does centripetal force affect centripetal force?

Centripetal acceleration is proportional to the square of the speed (a = v2/r). Therefore, according to Newton's Second Law, centripetal force is also proportional to the square of the speed.


How do you solve for revolutions per second give centripetal force and radius?

One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.


What is the formula in getting centripetal force and it's net horizontal force?

One formula for centripetal force is v2/2 - the square of the velocity (speed, actually) divided by the radius. Another is omega2r, where omega is the angular speed, in radians/second.One formula for centripetal force is v2/2 - the square of the velocity (speed, actually) divided by the radius. Another is omega2r, where omega is the angular speed, in radians/second.One formula for centripetal force is v2/2 - the square of the velocity (speed, actually) divided by the radius. Another is omega2r, where omega is the angular speed, in radians/second.One formula for centripetal force is v2/2 - the square of the velocity (speed, actually) divided by the radius. Another is omega2r, where omega is the angular speed, in radians/second.


3 What factors affect the increase of the centripetal force on a particle in uniform circular motion?

The centripetal force on a particle in uniform circular motion increases with the speed of the particle and the radius of the circular path. The mass of the particle also affects the centripetal force, as a heavier particle requires a stronger force to keep it moving in a circle at a constant speed.


What factors affect the increase of the centripetal force on a particle in uniform circular motion?

Increase in radius affect the increase of the centripetal force on a particle in uniform circular motion. An increase in radius would cause a decrease in the force if velocity remains constant.


How does speed affect centripetal force?

Force (newtons) = mass (kg) * acceleration ((m/s)/s) but > acceleration in a circle = velocity 2 / radius So > (centripetal) force = mass * (velocity 2 / radius)


If the radius of rotation and the mass being kept constant how does centripetal force vary with the speed of rotation body?

Centripetal force is directly proportional to the square of the speed of rotation. As the speed of rotation increases, the centripetal force required to keep the object moving in a circular path also increases. This relationship follows the formula Fc = mv^2 / r, where Fc is the centripetal force, m is the mass, v is the speed, and r is the radius of rotation.


If the radius of rotation and the mass being kept constant how does the centripetal force vary with the speed of rotation of the body?

Recall centripetal force = m v^2 / rAs m and r are found to be constants then centripetal force F is directly proportional to the square of the velocity of the body


What is the net force directed to the center of an objects circular path?

That is called the centripetal force. Its magnitude is speed squared / radius.That is called the centripetal force. Its magnitude is speed squared / radius.That is called the centripetal force. Its magnitude is speed squared / radius.That is called the centripetal force. Its magnitude is speed squared / radius.


What happens when speed of centripetal force is doubled?

If the speed of the centripetal force is doubled, the required centripetal force also doubles to keep the object moving in a circular path at that speed. The centripetal force needed is directly proportional to the square of the speed, so doubling the speed results in a quadrupling of the centripetal force required.