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jkjnl
4 years
That can be calculated from Kepler's 3rd law which says if the period is T years the semimajor axis must be T2/3 astronomical units. So for a period of 12 years the s/m axis is 5.421 AU or 784 million km.
Semimajor axis of its orbit, the average of the maximum and minimum distance from the Sun. <<>> That's basically the planet's average distance from the Sun.
The major axis is the diameter across the widest part. The semimajor axis is half that, and for a planet it's the average of the maximum and minimum distances from the Sun .
the period of revolution is related to the semimajor axis.... :)
jkjnl
4 years
One of the parts of an ellipse is the length of its major axis. Half that is called the semimajor axis. Kepler's 3rd law says that the time to do one orbit is proportional to the 3/2 power of the semimajor axis. IF the semimajor axis is one astronomical unit the period is one year (the Earth). For a planet with a semimajor axis of 4 AUs the period would have to be 8 years, by Kepler-3.
One of the parts of an ellipse is the length of its major axis. Half that is called the semimajor axis. Kepler's 3rd law says that the time to do one orbit is proportional to the 3/2 power of the semimajor axis. IF the semimajor axis is one astronomical unit the period is one year (the Earth). For a planet with a semimajor axis of 4 AUs the period would have to be 8 years, by Kepler-3.
That can be calculated from Kepler's 3rd law which says if the period is T years the semimajor axis must be T2/3 astronomical units. So for a period of 12 years the s/m axis is 5.421 AU or 784 million km.
Semimajor axis of its orbit, the average of the maximum and minimum distance from the Sun. <<>> That's basically the planet's average distance from the Sun.
The major axis is the diameter across the widest part. The semimajor axis is half that, and for a planet it's the average of the maximum and minimum distances from the Sun .
(I'm going to assume that when you said "first" you meant "fastest," because otherwise the question is nonsense.) Because of Kepler's Third Law. The orbital period for a body is related to the semimajor axis of its orbit. Mercury's orbit has the shortest semimajor axis of all the Solar planets, and therefore it has the shortest orbital period.
Not at all. The only thing that sets the orbital period is the semimajor axis, which is the average of the maximum and minimum distances from the Sun.
The major and minor axes of a circle are the same - either is any diameter. So a semimajor axis is half the diameter which is 12 cm.
From the point of view of a person on earth, the moon's period of rotation on its axis and revolution around earth are both 27.32 days. From the point of view of a person on the moon, the period of rotation on its axis and revolution around earth are both 27.32 [earth] days, and the period of revolution around the sun averages 365.24 earth days.