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150J, as the potential energy has been converted to kinetic energy as the swing accelerates downwards (and forwards) from the top of its swing. Therefore the decrease in potential energy corresponds directly to the increase in kinetic energy if we are ignoring things like friction. So KE = 200-50= 150
1. First, you want to convert cal to Joules (cal --> J).To do this, multiply the value of cal by 4.184 (1 cal = 4.184J)500cal x 4.184J = 2092J------------ 1 cal2. Calculate the change in internal energy of the gas (ΔU = heat – work).ΔU = 2092J heat - 500J work= 1595J change in internal energy
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Two different versions of the same airplane. There were several earlier versions of the aircraft, each with slight improvements or changes from the original. The 'J' model introduced a key operated electric starter, along with rocker type electrical switches to replace the older style "toggle" switches
150J, as the potential energy has been converted to kinetic energy as the swing accelerates downwards (and forwards) from the top of its swing. Therefore the decrease in potential energy corresponds directly to the increase in kinetic energy if we are ignoring things like friction. So KE = 200-50= 150
It depends! The older Monophasic (one shock per shock -one way) machines can use as much as 5000V. The newer Biphasic (two shocks per shock -back and forth) machines use around 2200V. Less energy= less heart damage risk. Now to some details: The energy output of these machines is termed in Joules. Usually something like 150J for a Biphasic or 200J in a Mono as a first shock. The critical part is that Joules are a product of the Voltage * Amperage * time (1 sec). Therefore in the above examples : 1500V * 0.1A * 1sec = 150J 2000V * 0.1A * 1 sec= 200J The high voltage is generated by converting either the mains power or the internal battery power to the required voltage via an inverter and then stored in a capacitor for rapid release when needed. As an example, cars usually run on a 12V system, BUT the energy sent to the spark plug from the ignition coil is massive and dangerous for a very short time, as is the energy during defibrillation. So, don't think your gloves will save you. Don't touch the patient when shocking them -as in don't continue compressions when shocking them. There is no such thing as an energy rated safe disposable medical glove. Hope this helps.
the cont 0-200 has a better fuel consumption rate. Check with your IA and he can tell you if that particular combination is an approved installation It is an approved installation; an Airframe and Powerplant shop files a Supplemental Type Certificate, the FAA signs off on it (the O-235 was used in the Cessna 152 so there's no real problem with the conversion) and the mechanic inserts the new engine in your classic airplane. One quick note: Lycoming is not shy about pricing its parts.
1. First, you want to convert cal to Joules (cal --> J).To do this, multiply the value of cal by 4.184 (1 cal = 4.184J)500cal x 4.184J = 2092J------------ 1 cal2. Calculate the change in internal energy of the gas (ΔU = heat – work).ΔU = 2092J heat - 500J work= 1595J change in internal energy