Given no air resistance or other forces acting on the projectile, the projectile falls at a rate of ~9.81 meters per second. Given the position equation is at^2 + vt + x, where a is acceleration, v is velocity, x is the starting position, and t is time. Given an initial velocity and time of zero, the object will have moved ~9.81 meters in the first second.
d = (vit) + (1/2)gt2
d = distance
vi = initial velocity = 0m/s
g = acceleration due to gravity = 9.8m/s2
t = time = 1s
d = (0) + (1/2)(9.8m/s2)(1s2) = 4.9m
The projectile will fall vertically 4.9m in 1s.
The initial rate refers to the rate at which a chemical reaction occurs at the beginning, when the reactants are first mixed together. It is determined by measuring the change in concentration of a reactant or product over a short period of time immediately after the reaction has started.
There is no SI unit for torque. Torque uses a compound unit such as Nm in the SI system. Also see 'related links' below
See below for a link to a list of all the expected landing times for the tsunami, from the National Oceanic and Atmospheric Administration. Note from the source: This list gives estimated times of arrival for locations along the North American Pacific coast from a tsunami generated at the given source location. THE LISTING OF A TSUNAMI ARRIVAL TIME BELOW DOES NOT INDICATE A WAVE IS IMMINENT. The listed arrival time is the initial wave arrival. Tsunamis can be dangerous for many hours after arrival, and the initial wave is not necessarily the largest.
Its 7Please see related link below!
If by "straight on" you mean at 90 degrees to the surface of the medium, that is because light is only deviated if it makes an angle with the normal, which is an imaginary line perpendicular to the surface of the medium. If no angle is made between the normal line and the light ray, then no refraction occurs and the light passes through in a straight line. For more information see the related link below.
It probably depends on your accent, see for yourself (see first link below) Wiktionary has it as the word-initial vowel (see second link below)
If the non-horizontal projectile is launched abovehorizontal, thenit's the second one to hit the ground, after the horizontal one.If the non-horizontal one is launched below horizontal, then it'sthe first to hit the ground, before the horizontal one.
On a horizontal straight line, three units below the x axis. On a horizontal straight line, three units below the x axis. On a horizontal straight line, three units below the x axis. On a horizontal straight line, three units below the x axis.
Affiliate programs generate revenue when those below the initial investor are able to generate. The potential for growth is exponential if those below the initial investor themselves entice others to join.
By the Way, guys, this is based on the equation H= -16t2+vt+s
1 sec : position = 10.1 metres above your hand, velocity = 5.2 ms^-1.40 sec : position = 7240 metres below your hand, velocity = 377 ms^-1 downwards.
A straight angle (180 degrees) makes a perfectly straight line. Any degree below 180 degrees (0-179 degrees) is NOT a straight angle NOR a straight line. straight angle = 180 degrees straight angle = straight line 180 degrees
If you were standing on a hill, with the wind to your back, and you fired a .45 ACP into the air at a 45 degree angle, with respect to the ground below, the projectile could easily travel a mile or more. This would NOT be very accurate, nor would the projectile be very powerful at the end of its trajectory.
Straight below moo moo
Straight in a glass. See also the related links below.
You need to state the time interval, then : u (initial velocity) = 3 feet per second a (acceleration due to gravity) = 32.174 (f/s)/s t = time interval (seconds) s = distance travelled (feet) So, according to newtons equation > s = ( u * t ) + ( 0.5 * a * t2 )
Germany See link below for information on the Second Crusade.