Geo-stationary communication satellites are 35,768 Km far from earth surface at an equatorial latitiude.
In order to appear motionless in the sky, the satellite must be in an orbit that is -- circular -- over the equator -- 22,400 miles above the surface
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To classify a satellite, one must consider its purpose, design, and operational parameters. Satellites can be categorized as communication, Earth observation, scientific research, navigation, or military. Each classification serves distinct functions and operates in various orbits, such as geostationary, polar, or low Earth orbit. The best classification depends on the satellite's primary mission and capabilities.
The plane of a satellite's orbit must include the center of the earth.
For a satellite to stay in one place over the earth, the satellite must be going in orbit in the same direction that the earth spins. The satellite must also travel at the same pace/speed as the earth spins to give us the 24-hour day that we as people witness. To apparently stay in one place it must be in a synchronous orbit. For the earth this is about 24,000 miles altitude. It must also be an equatorial satellite.
Because they can't provide worldwide coverage. To cover near-polar areas, inclined orbits are necessaries. Since the geostationary orbit must lay on the equatorial plane, it doesn't suit to fit GPS requirements.
No. A satellite in geostationary orbit remains stationary over a single point on the earth's equator. It must have an altitude of 22,236 miles above the earth, which makes its orbital period exactly one day. The moon is much too far away for that; its orbital period is 28 earth days.
If the satellite is anywhere near Earth's surface, it will take about one and a half hours to orbit Earth once. As the orbit gets higher, it will take longer - both because it must travel a longer distance, and because it will be slower.
If a satellite is in geosynchronous orbit, it will take the satellite 24 hours, a day, to orbit the Earth once. This is so because geosynchronous orbit is when a satellite orbit the Earth at such a time, that is is over the Earth at all times.
A geostationary satellite must orbit in the plane of the equator to be stationary. If launched from the equator it is already in that plane and only needs enough fuel to lift it and inject it into the right orbit. If launched from another point it will need extra fuel for maneuvering from its initial orbital plane into the equatorial plane. This gets worse with greater initial orbital inclination.
There is only one geostationary orbit because in order for any mass m to orbit the Earth (ME) the gravitational force: EQ1: Fg = GmME/r^2 has to be such that it is equal to the required centripetal force for uniform circular motion: EQ2: Fc = mv^2/r where v is the velocity of m at radius r (distance from the center of the Earth) and: EQ3: v = 2(pi)(r)(f) f is the frequency of rotation in revolutions per second. For geostationary orbit the satellite must be in a fixed position (it must have the same frequency of rotation or angular velocity as the Earth's rotation) relative to the Earth and orbit above the Earth's equator. The necessary velocity to satisfy Fg = Fc is a specific value, therefore (since pi and f are fixed values) r is the only variable in EQ3. There is a specific orbital radius for geostationary orbit of any mass m.
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