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If a ball that is freely falling has attained a velocity of 19.6 meters per second after 2 seconds. What is its velocity five seconds later?
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
For a freely falling object dropped front rest what is the acceleration at the end of the fifth second of the fall?
The object accelerates at 9.8 meters per second per second (9.8 m/s2), so for each second of free fall, its speed increases 9.8 m/s. So, the final velocity after five seconds is 5 x 9.8 = 49 m/s.
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