How far? In absence of air resistance, distance will be 24.522 meters (rounded).
The max. range that will be achieved will depend on how much faster you can throw that stone but for 16m/sec initial velocity it will only reach 24.522m at 35 degr. launch angle.
A stone is thrown with an angle of 530 to the horizontal with an initial velocity of 20 m/s, assume g=10 m/s2. Calculate: a) The time it will stay in the air? b) How far will the stone travel before it hits the ground (the range)? c) What will be the maximum height the stone will reach?
10 m/s
if the bal is thrown by making 45 degree angles. with the ground..it will travel maximum distance...
It is important when a heavy load is above the ground level, let's say the fridge on the truck which can not just be thrown to the ground so you need an incline plane for safety
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
As the rock rises, its horizontal component of velocity remains constant. This is because there is no horizontal force acting on the rock to change its velocity in that direction. The only force affecting the rock's motion is gravity, which acts vertically, causing its vertical component of velocity to decrease until the rock reaches its peak height and then falls back down.
No, this is an example of projectile motion. You should throw it at 45 degrees from the horizontal ground for it to have the maximum horizontal distance. This is because a sufficient height must be achieved, so that the ball can stay in the air longer and thus travel a longer distance while in flight.
horizontal
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
If the object is thrown upwards, the vertical acceleration is negative and the horizontal acceleration is zero.
If thrown horizontal from same height the faster object will travel farther horizontally, but time to fall is the same. If thrown straight up, the faster object will take longer to fall
The thrown ball will have a greater speed when it reaches ground level because it has a horizontal component of velocity in addition to the vertical component. The rock only has a vertical component of velocity due to gravity.
a stone is thrown from the top of a building with an initial horizontal velocity of 20 m/s if it is thrown from a height of 30 m and air resistance is neglected, find: a) time it takes the stone to reach the ground b) range
THE QUESTION: 2) A 5 kg object is thrown from the top of a building, 275m aboce some level ground. It is released at a speed of 45 m/s, initially along the horizontal direction. (A) What are the magnitude and direction of its velocity at impact on the ground below (B) what momentum does it have at impact (C) What KE does it have just before impact (D) What is the average force during the impact?
To find the maximum height, we first need to separate the initial velocity into its x and y components. Since the initial velocity is given as v = 7.6i + 6.1j, the initial vertical velocity is 6.1 m/s. We can use the kinematic equation for vertical motion: v_f^2 = v_i^2 + 2aΔy, where v_f = 0 at the maximum height. Rearranging the equation to solve for the maximum height, h, we have h = (v_i^2)/2g, where g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values, we find h ≈ 1.88 m.
17.8 meters
If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.