swagger
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
-- We can't say anything about the velocity, because we don't know anything about the horizontal motion of the ball. With the information included in the question, we can only be sure of how the vertical component of velocity behaves. -- At the maximum altitude of the ball, there's the instant where its vertical speed changes from upward to downward. At that instant, its vertical speed is zero.
A model rocket reaches maximum velocity at the point where the thrust from the engine matches the drag from the air, or the point where the thrust goes to zero when the fuel burns out, whichever comes first.
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
-- We can't say anything about the velocity, because we don't know anything about the horizontal motion of the ball. With the information included in the question, we can only be sure of how the vertical component of velocity behaves. -- At the maximum altitude of the ball, there's the instant where its vertical speed changes from upward to downward. At that instant, its vertical speed is zero.
A model rocket reaches maximum velocity at the point where the thrust from the engine matches the drag from the air, or the point where the thrust goes to zero when the fuel burns out, whichever comes first.
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
when the vertical component of its velocity is zero.
If you throw ball at an angle above horizontal, you will see the path of the ball looks like an inverted parabola. This is result of the fact that the ball's initial velocity has a horizontal and vertical component. If we neglect the effect of air resistance, the horizontal component is constant. But the vertical component is always decreasing at the rate of 9.8 m/s each second. To illustrate this, let the initial velocity be 49 m/s and the initial angle be 30˚. Horizontal component = 49 * cos 30, Vertical = 49 * sin 30 = 24.5 m/s As the ball rises from the ground to its maximum height, its vertical velocity decreases from 24.5 m/s to 0 m/s. As the ball falls from its maximum height to the ground, its vertical velocity decreases from 0 m/s to -24.5 m/s. Since the distance it rises is equal to the distance it falls, the time that it is rising is equal to the time it is falling. This means the total time is equal to twice the time it is falling. This is the reason that the shape of the ball's path is an inverted parabola. At the maximum height, the ball is moving horizontally. If you do a web search for projectile motion, you will see graphs illustrating this.
That varies depending on the monitor. You will have to read the specifications of the specific monitor that you want the answer for. There is no fixed maximum value.
A projectile will travel on a straight line unless external forces act upon it. Gravity will pull the projectile downward, i.e. affect its vertical velocity component. This is why the projectile will decelerate upwards, reach a maximum elevation, and accelerate back down to earth. The force vector of air resistance points in the opposite direction of motion, slowing the projectile down. For example, If the projectile is going forward and up, air resistance is pushing it backwards (horizontal component) and down (vertical component). Without air resistance, there is no external force acting upon the horizontal velocity component and the projectiles ground speed will stay constant as it gains altitude and falls back down to earth.
Assuming the simple model where the object is projected with an initial velocity of u metres/second at an angle of x to the horizontal, and that the only force acting on it after that is gravitational acceleration, g = 9.81 metres/second^2, then h = [u*sin(x)]^2/(2*g) metres.If the launch is vertical then x = pi/2 radians and h = u^2/(2*g) metres.
when a body is thrown at an angle in a projectile motion, the vertical component of the velocity is vcos(B) ..where v is the velocity at which the body is thrown and B represents the angle at which it is thrown.Similarly horizontal component is vsin(B). these components are useful in determining the range of the projectile ,the maximum height reached,time of ascent,time of descent etc.,
Both, a plane flying along loses both engines lets say, it'll change direction (from horizontal to vertical) and will pick up speed until it reaches maximum velocity, due to the downward force known as gravity.