How fast does a diver hit the water from 10 M high board?

Answer 1

A theoretical answer can be derived if you ignore energy losses (such as air resistance). Assume the diver starts off with a downward velocity of zero, and accelerates under gravity with no energy losses.

Thus his acceleration is equal to g (the gravitational field strength) in a downward direction. This is about 9.8 N kg-1, or 9.8 m s-2, depending on how you write it (both are equivalent).

At the top of his dive, he has a kinetic (moving) energy of zero, and potential energy given by:

PE = m g h

where m is his mass (in kilograms), and h is the height of the diving board (in this case, 10 metres)

This is converted into kinetic energy as he falls. When he hits the water, we can say that he has a potential energy of zero, and kinetic energy given by:

KE = m v2 / 2

Energy cannot be created or destroyed, so the potential energy at the top of the dive must be equal to the kinetic energy at the bottom.

m g h = m v2 / 2

g h = v2 / 2

2 g h = v2

v = (2 g h)1/2

= (2 x 9.8 m s-2 x 10 m)1/2

= 14 m s-1

The true value (allowing for air resistance) may be slightly lower than this.

Answer 2

it depends on the weight of the diver. is would be faster if the diver was a yougn child, forsay, and faster if it were a sumo wrestler!!

NO IT DOESN'T. Whoever posted that is an idiot! If you drop a feather, a Bowling ball, and a vacuum cleaner in a vacuum they will all fall at the same time, you idiot! You are stupid! The SA to weight is all that would matter in what you are referring to and not enough to matter in the presented circumstances!

~50k/h, by the way.

Answer 3

50400 meters per hour, or 50.4 Kph; about 31 mph

Answer 4

about 21mph