bh + (S1+ S2 + S3)H
bh+(S1+S2+S3)h
bh(s1+s2+s3)h
bh/2 + (S1+ S2 + S3)H
James H. Diamond died on 1945-05-14.
James H. Diamond was born on 1925-04-22.
The notation S1 is not used for diamonds -- SI[#] is used -- slightly included, and I[#] is used -- included. The number indicates a count of the visible flaws in a diamond under a 10x magnification. 'Pretty clear' can be used to describe most any gemstone, and is a judgement call, you being the judge.
The lateral area of a triangular prism is found by computing the perimeter of the triangular base (sum of the three sides) and multiplying it by the height of the prism. If the triangular base has sides of length s1, s2, and s3, and the height of the prism is h, then each lateral face of the prism would be a rectangle. The area of one face of the prism would be (s1 x h), the area of the second face of the prism would be (s2 x h), and the area of the third face of the prism would be (s3 x h). So the three lateral faces would have a total area of (s1 x h) + (s2 x h) + (s3 x h), or equivalently (s1 + s2 + s3) x h; i.e., (the perimeter of the triangular base) x (the height of the prism).
The highest grade for 'white' diamond colour is D, not A. D is a higher grade than H in diamond colour.
Answer: Surface area = bh/2 + (S1+ S2 + S3)Hin general surface area of a prism is2 × area of base + perimeter of base × HSo in particular, for the triangular prism, we have the answer above. Here is why.So h is the height of the triangular base and 1/2(bh) is the area of that triangle. 2x that isbh so that is where the bh part of the formula comes from.Now s1, s2 and s3 are the sides. So (s1+s2+s3) is the perimeter of the base. Let H be the height of the prism, then we have (s1+s2+s3)H in the second part of the formula.
s1 = side 1 s2 = side 2 and H = Hypotenuses12 + s22 = H2therefore H = square-root of (s12 + s22)
It depends on what the formula is for: volume, surface area, number of faces, number of edges, number of vertices, etc.Triangular Prism Formula :Area of Base(A) = ½ * a * bPerimeter of Base(P) = s1 + s2 + s3Surface Area of Prism = ab + (s1 + s2 + s3)h = ab + PhVolume of Prism = ½ * a * b * h = Ahwherea = altitude, b = base, h = height and s1, s2, s3 are sides