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Use the formula for gravitational potential energy (PE=mgh), and solve for height.
The object's velocity will be 109.54 meters per second.
Work = force x displacementW = Fd W = 100N x 3m W = 300J 300 joules of work is done on the box.
P.E=mgh =10.2 by 10 by 300 P.E=30,600J
The rock's PE is 29400 joules.
Use the formula for gravitational potential energy (PE=mgh), and solve for height.
W=FxD (work equals force times distance) 300j = F (50m) 300/50= 6 N OK, that assumes a constant force over the whole distance. N = Newtons (force)
The object's velocity will be 109.54 meters per second.
300 - 25% = 300 x (1 - (25/100)) = 300 x 0.75 = 225
[object Object]
Work = force x displacementW = Fd W = 100N x 3m W = 300J 300 joules of work is done on the box.
Work = force x displacementW = Fd W = 100N x 3m W = 300J 300 joules of work is done on the box.
P.E=mgh =10.2 by 10 by 300 P.E=30,600J
is 300 too high?
The rock's PE is 29400 joules.
To calculate the density of an object, divide the mass (54) by the volume (300). The answer is about 5.
300 ones equal 3 hundreds