In order for a star to form, gas from an interstellar cloud has to be gravitationally attracted toward a center of gravity. The strength of the gravitational attraction depends upon the amount of mass (and its density, which of course increases as the star is in the process of being formed). It takes a certain amount of mass to create a star, otherwise all you will have is an interstellar gas cloud.
Hydrostatic equilibrium has nothing to do with the mass of the star but the compression, due to gravity, balanced by pressure of the star.
See the related question.
Hydrostatic equilibrium occurs when compression, due to gravity, is balanced by a pressure gradient, which creates a force in the opposite direction. In stars, the pressure gradient appears as a result of the huge quantity of thermal energy (which acts outward) created by nuclear fusion reactions. It is gravity and this thermal energy that are in equilibrium.
It's a bit like blowing a balloon up, the inward pressure is counteracted by the external pressure of the atmosphere. In addition, when we consider stars, this means that the larger the mass of the star, the higher the temperature must be to achieve this balance. Larger stars will use up their supply of hydrogen more quickly and live a shorter life.
Mass. The larger the star, the faster it consumes its fuel.
Mass. That's all; everything about a star is determined by the initial mass.
A star's luminosity depends on two characteristics: sizeand temperature of star.
Anywhere between a few millions and trillions of years, depending mainly on the star's mass.
It depends on it's size
They weigh each star with a scale
Mainly on its mass.
No, how a star dies is determined by its mass.
Yes, a stable star is in equilibrium, called hydrostatic equilibrium, when the outward pressure from heat caused by core fusion processes balances the inward pull of gravity. There are other factors which alter the form of stars such as their rotation or gravity from external sources such as a nearby mass.
binary star systems
Massive stars get hotter, burn their fuel faster, and therefore live shorter.With respect to their "death": Stars of "normal" mass become white dwarves; more massive stars become neutron stars, and the most massive stars become black holes.
Yes.
Hydrostatic and Equilibrium
hydrostatic equilibrium
The properties of a main-sequence star can be understood by considering the various physical processes occurring in the interior. First is the hydrostatic balance, also called hydrostatic equilibrium. This determines the density structure of the star as the internal pressure gradient balances against the force of gravity.
No, how a star dies is determined by its mass.
Hydrostatic equilibrium [See related question]
Yes, a stable star is in equilibrium, called hydrostatic equilibrium, when the outward pressure from heat caused by core fusion processes balances the inward pull of gravity. There are other factors which alter the form of stars such as their rotation or gravity from external sources such as a nearby mass.
Hydrostatic equilibrium occurs when compression due to gravity is balanced by a pressure gradient which creates a pressure gradient force in the opposite direction. The balance of these two forces is known as the hydrostatic balance.
Binary stars are ideal to determine the mass of the components.
Any star is going to be in hydrostatic equilibrium, so "shape" is not really a factor.
They weigh each star with a scale
binary star systems
Hydrostatic resistance is another term of hydrostatic pressure. This is the pressure exerted by a fluid due to the force of gravity. This increases with depth because of the increasing weight of the fluid above a certain point.