An object will float if it is less dense than the liquid in which it is placed; if it is denser, it will sink. In terms of forces, if the force of gravity (downward) is greater than the buoyant force (upward), then of course the net force will be downward, and the object will sink.
The force that will push upwards on an object put in water is called buoyancy. Archimedes discovered and accurately described the specifics of this phenomenon over 2000 years ago, and Archimedes' principle is still used today.
Never. Because buoyant force is equal to the weight of the displaced liquid. The same volume would get diplaced even though the depth is changed
Since acceleration involves a change in velocity, and object might be accelerating even though its speed is constant.
Expansion. Depends on the object's composition though.
don't know, only three though
Not sure what you are looking for. This is Archimede's principle though, A buoyant object experiences an upward force, and at the same time displaced the medium in which it is placed. Is that what you were looking for? Basically...you float
Never. Because buoyant force is equal to the weight of the displaced liquid. The same volume would get diplaced even though the depth is changed
The force that will push upwards on an object put in water is called buoyancy. Archimedes discovered and accurately described the specifics of this phenomenon over 2000 years ago, and Archimedes' principle is still used today.
Though it is not possible to say: I like, in Spanish, the equivalent would be: me gusta which literally means: (xxx) is pleasing to me. The emphasis is on the object liked, and not on the person 'liking' the object.
Since acceleration involves a change in velocity, and object might be accelerating even though its speed is constant.
If measuring from sea level, yes. Technically, though, it is accurate to state depth as a negative number, but unless you have been specifically told, it shouldn't matter whether you do or not. The only exception I can think of is if you are drawing a parabola that shows the depth of a buoyant object over a period of time after being thrown or dropped in. It looks a lot neater to show a positive parabola, as a negative parabola could imply that a non-buoyant object was thrown from the bottom of a body of water. I hope this helped, and ignore the previous paragraph if you want.
no. 18 or more daily and you're pushing it though.
Expansion. Depends on the object's composition though.
don't know, only three though
Friction. Since "air" is not a vacuum, it takes energy to move through it in the same way it takes energy to move through water. (though this is a more drastic example.) If there is no active energy source to keep an object pushing past the particles in the air (like a propeller or rocket) it will slow down as it loses momentum.
No. A nonzero acceleration means that the velocity is changing, so it can only have a 0 velocity at a single point in time, such as when a ball thrown in the air reaches its peak.
It is possible. You'll have to change your piping though.