The impact of an event happening at a distance takes some time to reach the observer. This is the lag time and, as the distance increases, the lag time increases. The increase depends on the velocity of transmission of the information.
For example, the lag time for a flash of lightning depends on the speed of light; the lag time for the clap of thunder depends on the speed of sound; the lag time for the person that the lightning bolt missed depends on how fast they can run to you.
If the average speed of the car....Here is an unfinished question. The total distance is average speed times time. But since average speed is gotten by dividing total distance by the time, then it's a kind of circular question.
Generally: RATE = DISTANCE / TIME -or- DISTANCE = RATE * TIME -or- TIME = DISTANCE / RATE qed
Distance = Rate x Time Rate = Distance/Time, not Time/Distance
Speed is distance divided by time, but distance times time is not a recognizable quantity.
Average speed during the time = (distance) divided by (time for that distance)
It Also Increases
It Also Increases
The more is the time taken and the distance recorded by the seismograph, the more is the effect of an earthquake:)
20 km
4,000 kilometers
Jet lag usually lasts 24-48 hours after travel has taken place. In that short time period, the body adjusts to the time change, and with enough rest and daytime exposure to sunlight, it returns to normal circadian rhythm.
Inside lag is the time to implement (pass) a policy, while outside lag is the time it needs to take effect.
Yes.
a diaphragm displacement gives 2 possible pressures, elastic after-effect finally compensates the measurement --> time lag
no time lag.................
An event occuring at time t+k is said to lag behind event occurring at time t. Extent of lag is k.
It will take less time.