The logarithm function is defined so that if
y = 10x then log y = x
So, if x = 1, y = 101 = 10
and so log 10 = 1
logx(3) = log10(7) (assumed the common logarithm (base 10) for "log7") x^(logx(3)) = x^(log10(7)) 3 = x^(log10(7)) log10(3) = log10(x^(log10(7))) log10(3) = log10(7)log10(x) (log10(3)/log10(7)) = log10(x) 10^(log10(3)/log10(7)) = x
log10(225)2 equals 5.5327625985087111
pH means -log10(H+concentration) so pH of a H+ concentration 3.6x10-9 is: pH = -log10(3.6x10-9) ≈ 8.4
Say you have some integer a. aFirst take it's absolute value. |a|Next log it base 10. log10 |a|Truncate this value, then add 1. trunc ( log10 |a| ) + 1You now have the number of digits.
The natural logarithm is calculated to base e, where e is Euler's constant. For any number, x loge(x) = log10(x)/log10(e)
logx(3) = log10(7) (assumed the common logarithm (base 10) for "log7") x^(logx(3)) = x^(log10(7)) 3 = x^(log10(7)) log10(3) = log10(x^(log10(7))) log10(3) = log10(7)log10(x) (log10(3)/log10(7)) = log10(x) 10^(log10(3)/log10(7)) = x
log10(225)2 equals 5.5327625985087111
To calculate the pH of the solution, you need to consider the dissociation of benzoic acid and sodium benzoate. Since benzoic acid is a weak acid, it will partially dissociate, while sodium benzoate will fully dissociate into its ions. Together, they will create a buffer solution. You will need to calculate the concentrations of the acid and conjugate base, use the Henderson-Hasselbalch equation, and consider the ionization constant of benzoic acid to determine the pH.
4
The pH of a solution with [H+] = 7.0 x 10^-2 M is pH = -log(7.0 x 10^-2) = 1.15.
There is no simple answer. 10 to the power 1.995635 (approx) = 99 The number 1.995635 is log10(99)
pH means -log10(H+concentration) so pH of a H+ concentration 3.6x10-9 is: pH = -log10(3.6x10-9) ≈ 8.4
pH s calculated as the negative log10 of the hydrogen ion concentration. So log10 of 0.000724 = -3.14 so pH= 3.14
log10 0 is actually undefined. Think about it like this: If loba b = y then we know that ay = b This means that log10 0 = y translates to 10y = 0 But as you know, 10y is always greater than zero. Therefore 10y = 0 is undefined. Therefore log10 0 = y is undefined.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals".
Let us assume you have a Hydrochloric acid solution of 0.1 M. The pH is - log10[H+]. So log10[0.1] = -1 easy way to remember this is 103 =1000 log 101000 = 3 102 =100 log 10100 = 2 101 =10 log 1010 = 1 100 =1 log 101 = 0 10-1 =0.1 log 100.1 = -1 10-2 =0.01 log 100.01 = -2 So log10[0.1] = -1 and thus pH is - log10[H] = (minus minus 1) = 1
xlog10 = x This is a simple rule of logs, because log(base10)10 = 1. Any value multiplied by one equals itself. So pi*log10 = pi(1) = pi.